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3 years ago

6

An airport parking lot charges a basic fee of $2 plus $1 per half-hour parked. Write an equation for the total charge, c,in term

s of the number of half-hours parked,h.

1 answer:

skad [1K]3 years ago

4 0

Answer:

$1h + $2

Step-by-step explanation:

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HEB has dish soap that costs $2.80 for a 12oz bottle. Fiesta has the same dish soap that costs $2.00 for a 8 oz tube.

s2008m [1.1K]

Answer:

The unit rate at HEB is $0.23 per ounce. The unit rate at Fiesta is $0.25 per ounce. So HEB has the better buy for dish soap.

Step-by-step explanation:

To calculate unit rate, you divide the price by the oz.

So for HEB, you should do $2.80/12 oz. This will equal to $0.23 per ounce. For Fiesta, you should do $2.00/8 oz. This will equal to $0.25 per ounce.

To determine which one is the better buy, the lower priced one is better, meaning HEB is the better buy.

4 0

3 years ago

please help me ASAPif asked is this a text or a quiz- this is a practiceif asked if a agree to the terms and guidelines- I agree

STatiana [176]

We notice that the common ratio of teh sequence is 10, and that the first term is -0.56, then the recursive formula is:

$a_{n+1}=a_n\cdot10,a_1=-0.56$

3 0

8 months ago

Welppp fastttt!!!!!!!!!!!!!!!!!!

Romashka [77]

Answer: B

Step-by-step explanation:

Grade must be greater than or equal to 88

7 0

2 years ago

Read 2 more answers

Hat term can you add to StartFraction 5 over 6 EndFraction x minus 4 to make it equivalent to One-half x minus 4?

kolezko [41]

Answer:

$\dfrac{-x}{3}$ should be added to the given equation.

Step-by-step explanation:

Let a is added to the given equation.

According to the given condition,

$\dfrac{5x}{6}-4+a=\dfrac{x}{2}-4\\\\a=\dfrac{x}{2}-4+4-\dfrac{5x}{6}\\\\a=\dfrac{x}{2}-\dfrac{5x}{6}\\\\a=\dfrac{3x-5x}{6}\\\\a=\dfrac{-2x}{6}\\\\a=\dfrac{-x}{3}$

So, $\dfrac{-x}{3}$ should be added to the given equation.

8 0

2 years ago

The cost CC (in dollars) of making nn watches is represented by C=15n+85C=15n+85. How many watches are made when the cost is $38

dangina [55]

$\bf \stackrel{cost}{C}=15\stackrel{watches}{n}+85\qquad \boxed{C=385}\qquad \stackrel{cost}{385}=15n+85
\\\\\\
380=15n\implies \cfrac{380}{15}=n\implies \cfrac{76}{3}=n\implies 25\frac{1}{3}=n$

so, 25 whole watches and hmmmm just the wristband of another maybe.

5 0

3 years ago