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3 years ago

Jeremy gives his horse 12 gallons of water each day how many 1 quart pails of water is that

2 answers:

6 0

One gallon of water equals four quarts of water. 1 times 12 equals 12. 4 times 12 equals 48. Jeremy's horses get 48 pails of water a day.

hjlf3 years ago

4 0

Hey! Hope that I can help. 1 gallon = 4 quarts, so 12 x 4 = 48 quarts.

You might be interested in

Find the value of x in the triangle shown below.

MrMuchimi

Answer: 102 degrees

Step-by-step explanation:

This is an isosceles triangle because two of the sides are the same length which means that two angles are congruent as well.

180-(2(39))

=180-(78)

=102

5 0

3 years ago

2+1.25f=10−2.75f solve for f

Inga [223]

Hey there!

2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.

1.25f + 2.75f = 4f

4f + 2 = 10
Subtract 2 from both sides.

4f = 8
Divide both sides by 4 to solve for f.

f = 2

I hope this helps!

6 0

3 years ago

Examine the right triangle. A right triangle with side lengths 17 centimeters and 48 centimeters. The hypotenuse is unknown. Wha

Dimas [21]

Answer:

The answer to your question is c = $\sqrt{2593}$

Step-by-step explanation:

Data

right triangle

short leg = 17 cm

long leg = 48 cm

hypotenuse = ?

Process

-Use the Pythagorean theorem to find the answer

c² = a² + b²

c = hypotenuse

a = short leg = 17 cm

b = long leg = 48 cm

- Substitution

c² = 17² + 48²

-Simplification

c² = 289 + 2304

c² = 2593

-Result

c = $\sqrt{2593}$

5 0

3 years ago

Read 2 more answers

A circular plate has a radius of 13 centimeters.

butalik [34]

To solve the problem, we need to get the formula for area of a circle -
Area = pi * r^2; r= radius
= 3.14 * (13cm)^2
= 3.14 * 169cm^2 or 3.14 * 13^2cm^2
= 530.66cm^2
Therefore, the area of the circular plate is 530.66cm^2

3 0

3 years ago

Read 2 more answers

What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x

lora16 [44]

$\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}$

We can begin by rearranging this into multiplication:

$\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}$

Now we can factor the numerators and denominators:

$\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}$

The factors (x+4) and (x+2) cancel out, leaving us with:

$\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}$

Our answer comes out to be:

$\frac{(x-4)^{2} }{(x+3)(x+1)}$ or $\frac{ x^{2} -8x+16}{ x^{2}+4x+3 }$

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4

4 0

3 years ago