Answer:
D) (-3, 0) and (1, 2).
Step-by-step explanation:
5x^2 + y^2 - x + 20y - 48 = 0
x - 2y + 3 = 0
From the second equation:
x = 2y - 3 , so we substitute this in the first equation:
5(2y - 3)^2 + y^2 - (2y - 3) + 20y - 48 = 0
5(4y^2 - 12y + 9) + y^2 - 2y + 3 + 20y - 48 = 0
20y^2 - 60y + 45 + y^2 - 2y + 3 + 20y - 48 = 0
21y^2 - 42y = 0
21y(y - 2) = 0
y = 0 , 2.
So when y = 0 x = 2(0) - 3 = -3
and when y = 2 , x = 2(2) - 3 = 1.
