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evablogger [386]
3 years ago
10

Solve the system of equations below algebraically.

Mathematics
1 answer:
harkovskaia [24]3 years ago
4 0

Answer:

D)  (-3, 0) and (1, 2).

Step-by-step explanation:

5x^2 + y^2 - x + 20y - 48 = 0

x - 2y + 3 = 0

From the second equation:

x = 2y - 3 , so we substitute this in the first equation:

5(2y - 3)^2 + y^2 - (2y - 3) + 20y - 48 = 0

5(4y^2 - 12y + 9) + y^2 - 2y + 3 + 20y - 48 = 0

20y^2 - 60y + 45 + y^2 - 2y + 3 + 20y - 48 = 0

21y^2 - 42y = 0

21y(y - 2) = 0

y = 0 , 2.

So when y = 0 x = 2(0) - 3 = -3

and when y = 2 , x = 2(2) - 3 = 1.

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3 years ago
Correct answer only need urgent help
Andreas93 [3]

Answer:

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8 0
2 years ago
Polly has a very rain number of dollar bills in her purse and no change.She spends half the money on a scarf and gives $1dollar
miss Akunina [59]

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3 0
3 years ago
NEED HELP PLS FOR BOTH!!!
Kipish [7]
39/500 needs to be multiplied by 15, which results in 585/500. This is 1.17 as a decimal. 191/200 in diameter needs to be multiplied by 8, which equals 1528/200. This is 7.64 as a decimal.
4 0
3 years ago
A number was subtracted from 15. After which, that result was multiplied by 5. This result was then divided by 5 for a result of
likoan [24]

Answer:

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