$perimeter \: of \: rectangle \\ = 2(17.8 + 13.4) \\ = 2 \times 31.2 \\ = 62.4 \: cm \\ \\ area \: of \: rectangle \\ =17.8 \times 13.4 \\ = 238.52 \: {cm}^{2} \\$

8 0

2 years ago

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The son is 22 years younger than his father, in 4 years the father is 3 times as old as the son. How old are father and son now?

Ganezh [65]

Step-by-step explanation:

Let the son's present age be x years

$\therefore$ Father's present age = (x + 22) years.

Four years after:

Son's age = (x + 4)

Father's age = (x + 22 + 4) =(x + 26) years.

According to the given condition:

Father's age = 3 times the son's age

$\therefore \: x + 26 = 3(x + 4) \\ \therefore \: x + 26 = 3x + 12 \\ \therefore \: 26 - 12= 3x - x \\ \therefore \: 14= 2 x \\ \therefore \: x = \frac{14}{2} \\ \huge \red{ \boxed{ \therefore \: x = 7}} \\ \\ \implies \: x + 22 = 7 + 22 \\ \huge\red{ \boxed{ \therefore \:( x + 22)= 29}}$

Hence, now :

Father's age = 29 years

Son's age = 7 years.

Let us move to the next part of the question:

Let y years ago father's age was 12 times his son.

y years ago

son's age = (7 - y) years

Father's age = (29 - y) years

$\therefore\: 29 - y = 12(7 - y)\\\\\therefore\: 29 - y = 84 - 12y\\\\\therefore\: 12 y - y = 84 - 29\\\\\therefore\: 11y = 55\\\\\therefore\: y = \frac{55}{11}\\\\\huge\orange{\boxed {\therefore\: y = 5}}$

Thus, 5 years ago father's age was 12 times than his son.

8 0

2 years ago

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There are 18 students attending band camp,4 girls and 14 boys. wht is the ratio of girls to boys at band camp?

Triss [41]

Answer:

Step-by-step explanation:

4÷2=2

14÷2=7

making it a equal ratio

4 0

2 years ago