1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arisa [49]
3 years ago
5

You are a plumber, and you are repairing a toilet leak. The job should take 0.9 hours. About how many minutes will it

Mathematics
2 answers:
monitta3 years ago
6 0

Answer:

54

Step-by-step explanation:

multiply 60 by 0.9 and you get 54..?

anzhelika [568]3 years ago
3 0

Answer:

54

Step-by-step explanation:

0.1 is 10% of 1 and was subtracted off so we subtract 10% off 60 so 60 x 10% = 6

60 - 6 = 54

Hope this helps can I have brainliest

You might be interested in
3. Tickets to a baseball game cost $22 each and parking costs $10. What is the equation of the line that represents the cost of
kirill115 [55]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can you construct a triangle that has side lengths 1 cm, 15 cm, and 15 cm?<br> yes or no ?
lana66690 [7]
Yes, I believe you can
4 0
3 years ago
Read 2 more answers
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
0.2(x + 1) + 0.5x = -0.3(x - 4)?
andreyandreev [35.5K]

Answer:

x=1.....................

7 0
3 years ago
What two numbers when added equal 25 and when multiplied = -200
Igoryamba
The numbers are irrational, so I can't write them exactly with digits.
When rounded to the nearest ten-thousandth, they are

       31.3746
and
       -6.3746 .
3 0
3 years ago
Other questions:
  • How to write 41.344 in word form
    5·2 answers
  • Q: How does period relate to music or sound?
    7·1 answer
  • Solve for x.<br><br><br><br> Enter your answer in the box.<br><br> x = <br> °
    9·2 answers
  • Explain how you can compare the cost of two items that are different sizes.
    8·1 answer
  • Match the following equation to the correct situation.
    15·1 answer
  • First person to get it right gets brainliest
    13·1 answer
  • What is the median?<br> A(18<br> B(27<br> C(33.2<br> D(34.5
    10·2 answers
  • If an investor wants to earn $250 simple interest by investing $600 at 4.5% annual interest, how many years will it take for her
    10·1 answer
  • What must be true about the coordinates of any point that lies in the third quadrant?
    9·1 answer
  • I can bake 3/4 of a cake in 5 minutes. How much of the cake canlbake in 1 minute?​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!