Pfvr algm me ajuda nessa
1 answer:
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1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula to find the distance from point
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: .
Answer:
<h2>y + 3 = -6(x + 9) - point-slope form</h2><h2>y = -6x - 57 - slope-intercept form</h2>Step-by-step explanation:
The point-slope form of an equation of a line:
<em>m</em><em> - slope</em>
The formula of a slope:
========================================
We have the slope <em>m = -6</em> and the point (-9, -3).
Substitute:
Convert to the slope-intercept form (<em>y = mx + b</em>):
<em>use the distributive property</em>
<em>subtract 3 from both sides</em>