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slamgirl [31]
3 years ago
8

Yuri has 2/7 of a bag of carrots if she eats half of the carrots what fractions of the bag of carrots will she have left

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

14/100 is half of 2/7.

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11. Little Sally Walker has a choice between going to an in-state college where she would pay
nalin [4]

Answer:

Step-by-step explanation:

Lets calculate first for in state college

yearly tuition fees = $3,500

monthly living expense = $700

one year has 12 months so yearly living expense =$700 * 12 = $8,400

Yearly expense of the in state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $3,500 + $8,400  = $11,900

____________________________________________________

Lets calculate first for  out of state college

yearly tuition fees = $6,000

monthly living expense = $400

one year has 12 months so yearly living expense =$400 * 12 = $4,800

Yearly expense of the out of state college = yearly tuition fees ($3,500 )+ yearly living expense($8,400)   = $6,000 + $4,800  = $10,800

____________________________________________________

3 0
3 years ago
Compare using &gt;, &lt;, or =.<br><br> 3 miles_5,000 yards
lina2011 [118]

Answer:

3 miles = 5280 yds

5280 yds > 5,000 yds

in this case 3 miles is greater than 5,000 yards

4 0
3 years ago
Find the vertex.<br> f(x)<br> =<br> 2(x + 7)2 + 8<br> ([?],[ ]
Nana76 [90]
(-7,8)

Simplifying 2(x+7)^2+8
Will give you the image results

You must graph the formula and you’ll get -7,8 (using desmos helps)

6 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
What is (9−7)×9−9+3? Use order of operations to evaluate the expression below.
Mumz [18]

Answer:

12

Step-by-step explanation:

I did order of operations, GEMA OR PEMDAS, etc.

5 0
3 years ago
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