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2 years ago

How can help me on this the blank one if the one I need help one btw

Mathematics

2 answers:

adell [148]2 years ago

8 0

Yeah the answer is zero. Because when you add a positive and a negative together it will always cancel each other out

Serga [27]2 years ago

6 0

Answer:

Step-by-step explanation:

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Please help me........

kati45 [8]

Answer:

x = 54

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Equality Properties

Step-by-step explanation:

Step 1: Define

-12(x + 4) + 14x = 60

Step 2: Solve for x

Distribute -12: -12x - 48 + 14x = 60
Combine like terms: 2x - 48 = 60
Add 48 to both sides: 2x = 108
Divide 2 on both sides: x = 54

7 0

3 years ago

Read 2 more answers

Maya thinks there are twice as many players in the league with more than 4 years of experience than there are players with less

iragen [17]

Sorry don’t now the answer to this problem

6 0

3 years ago

X + 3/2 = 3/4 (x - 1/2)

Iteru [2.4K]

this would be your answer, x = 1 - 15/2.

Thanks,

Deku ❤

8 0

3 years ago

5 more than the product of a number and 4 is equal to 3 use variable y for unknown number

Inessa05 [86]

Answer:

$(y + 4) + 5 = 3 \\ y + 9 = 3 \\ y = - 6 \\$

I'm not sure

8 0

3 years ago

Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even

Allushta [10]

Answer:

$P(E|A)= \frac{10}{11}$

Step-by-step explanation:

Given

Two rolls of die

$E \to$ one of the outcomes is 6

$A \to$ atleast one is 6

Required

P(E|A)

First, list out the outcome of each

$E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

So:

$P(E|A)= \frac{n(E\ n\ A)}{n(A)}$

Where:

$E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$n(E\ n\ A) = 10$

$n(A) = 11$

So:

$P(E|A)= \frac{10}{11}$

7 0

2 years ago