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3 years ago

In a school of 1600 students, the ratio of teachers to students is 1:16.

Mathematics

1 answer:

a_sh-v [17]3 years ago

4 0

Answer:

The number of teacher who joined the school is 20

Step-by-step explanation:

Teacher : Students = 1 : 16

Number of teachers = 1x

Number of students = 16x

16x = 1600

x = 1600/16

x = 100

Number of teachers at the beginning = 100

Now, after some teachers (let it be y) joining the school,

Teacher : students = 3:40

$\frac{100+y}{1600}=\frac{3}{40}\\\\40*(100+y)=3*1600\\\\4000+40y = 4800\\\\40y=4800-4000\\\\40y=800\\\\y=\frac{800}{40}\\\\y=20$

The number of teacher who joined the school is 20

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Leto [7]

The value of f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Given a function f(x)=4-2x+6 $x^{2}$ .

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6 $a^{2}$ (By just putting x=a).

f(a+h)== $4-2(a+h)+6(a+h)^{2}$

=4-2a-2h+6( $a^{2} +h^{2} +2ah$ )

=4-2a-2h+6 $a^{2} +6h^{2} +12ah$

= $6a^{2} +6h^{2}-2a-2h+12ah$

[f(a+h)-f(a)]/h=[ $6a^{2} +6h^{2}-2a-2h+12ah$ -(4-2a+6 $a^{2}$ )]/h

= $(6a^{2} +6h^{2} -2a-2h+12ah)/h$

= $(6h^{2} -2h+12ah)/h$

=6h+12a-2.

Hence the value of function f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Learn more about function at brainly.com/question/10439235

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