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irina [24]
3 years ago
10

The sum of two numbers is

Mathematics
2 answers:
Montano1993 [528]3 years ago
7 0
The numbers are 15 and 2.6 
ps sorry I type really slow 

kogti [31]3 years ago
5 0
Set up the equation
x = the smaller number
x + 15 = the larger number

x + x + 15 =39
solve for x
this will be the smaller number
add 15 to get the larger number
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bob has 64 cups. could he distribute them into 6 equally in stacks and not have any left over? Explain
Iteru [2.4K]

Bob cannot distribute the cups in six equal stacks and not have any left over.

Step-by-step explanation:

In order to divide the total number of cups in six equal stacks with no left over, the total number of cups will be divided by 6, if there is any remainder then the cups cannot be equally divided with no left over.

So

Dividing 64 by 6

= \frac{64}{6} \\= 10\frac{4}{6}

Here

Quotient = 10

Remainder = 4

As there are 4 cups left, Bob cannot distribute the cups in six equal stacks and not have any left over.

Keywords: Division, fractions

Learn more about division at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

8 0
3 years ago
Help <br> me to solve this please
Leona [35]

Answer:

for this one I think it mostly 3

3 0
3 years ago
My question is what is the answer to 2y = x + 3 <br> x = y
Brilliant_brown [7]

Answer:

(0,0)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
Which could be the name of a point?
lakkis [162]
I believe the answer is A or C because capital letters are used to name a point

6 0
3 years ago
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