Ask question

Ask question

All categories

3 years ago

14

Dylan has a 32-ounce coffee.He drinks 4 ounces. What is the percentage of ounces left of his coffee?

1 answer:

Semenov [28]3 years ago

8 0

$32 \div 100 = 3.125 \\ \\ 3.125 \times 4 = 12.5 \\ \\ 100 - 12.5 = 87.5 \\ \\ 87.5$

You might be interested in

Find the least common denominator of the two fractions 3/4 over 1/6?

leva [86]

Answer:

(2/12 & 9/12)

Step-by-step explanation:

12 is the least common denominator for the fractions, so they must be rewritten to have the same denominator, but hold the same value.

( not written by me )

8 0

3 years ago

Read 2 more answers

4. Which of the following is parallel to the line y = 1 +1 ?

aliina [53]

Answer:

A

Step-by-step explanation:

6 0

2 years ago

How do you identify the center and radius of each . Then sketch the graph.

lana [24]

All is in the file. The graph and formulas.

3 0

3 years ago

How many days are in a monthly billing cycle that ends on Feb. 13?

STatiana [176]

Answer:

31 days?

Step-by-step explanation:

There are 31 days from Janurary 13 to Feburary 13.

8 0

3 years ago

37. Socks. In your sock drawer you have 4 blue socks, 5 grey socks, and 3 black ones. Half asleep one morning, you grab 2 socks

mihalych1998 [28]

Answer:

a) $\frac{1}{22}$

b) $\frac{7}{22}$

c) $\frac{5}{11}$

d) $\frac{35}{66}$

Step-by-step explanation:

Given,

Number of blue socks = 4,

Grey socks = 5,

Black socks = 3,

Total socks = 4 + 5 + 3 = 12,

Ways of choosing any 2 socks = $^{12}C_2$

$=\frac{12!}{2!10!}$

$=\frac{12\times 11}{2}$

$=6\times 11$

= 66,

a) Ways of choosing 2 blue socks = $^3C_2$

= 3,

Since, $\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Thus, the probability of selecting 2 blue socks = $\frac{3}{66}=\frac{1}{22}$

b) Ways of choosing 2 shocks, non of them are grey socks = $^7C_2$

$=\frac{7!}{2!5!}$

$=7\times 3$

$=21$

Thus, the probability of selecting no grey socks = $\frac{21}{66}$

$=\frac{7}{22}$

c) ways of selecting atleast 1 black sock = ways of selecting 1 black sock + ways of selecting 2 black socks

$=^3C_1\times ^9C_1+^3C_2$

$=3\times 9 + 3$

$=27 + 3$

= 30,

Thus, the probability of selecting at least 1 black sock = $\frac{30}{66}$

$=\frac{5}{11}$

d) Ways of selecting a green sock = $^5C_1\times ^7C_1$

= 35,

Thus, the probability of selecting a green sock = $\frac{35}{66}$

3 0

3 years ago