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Illusion [34]
3 years ago
14

Dylan has a 32-ounce coffee.He drinks 4 ounces. What is the percentage of ounces left of his coffee?

Mathematics
1 answer:
Semenov [28]3 years ago
8 0

32 \div 100 = 3.125 \\  \\ 3.125 \times 4 = 12.5 \\  \\ 100 - 12.5 = 87.5 \\  \\ 87.5
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For two years, two samples of fish were taken from a pond. Each year, the second sample was taken six months after the first sam
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Answer : trout increased B

Step-by-step explanation:

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3 years ago
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How many unique triangles can be drawn with given side lengths of 8 inches,10.3 inches,and 13 inches?​
goldfiish [28.3K]

Answer:

3 unique triangles

Step-by-step explanation:

If you use the Triangle Inequality Theorem, it states that the sum of 2 sides of the triangle would equal more than the third side. So three triangles can be made with those side lengths.

3 0
3 years ago
Please help me with this translating trigonometry graphs question. Brainliest and Points Available.
andreev551 [17]

According with the definition of translation, we conclude that the equations of graphs M and N are m(x) = f(x - 5) and n(x) = f(x) - 2, respectively.

<h3>How to apply translations on a given function</h3>

<em>Rigid</em> transformations are transformation such that the <em>Euclidean</em> distance of every point of a function is conserved. Translations are a kind of <em>rigid</em> transformations and there are two basic forms of translations:

Horizontal translation

g(x) = f(x - k), k ∈ \mathbb {R}     (1)

Where the translation goes <em>rightwards</em> for k > 0.

Vertical translation

g(x) = f(x) + k, k ∈ \mathbb {R}     (2)

Where the translation goes <em>upwards</em> for k > 0.

According with the definition of translation, we conclude that the equations of graphs M and N are m(x) = f(x - 5) and n(x) = f(x) - 2, respectively.

To learn more on translations: brainly.com/question/17485121

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3 0
2 years ago
Cna i get some help with dis plz
Tomtit [17]

Let b_1,b_2,\ldots,b_{20} be the 20 marks of the boys, and g_1,g_2,\ldots,g_{10} be the 10 marks of the girls.

We know that the global mean was 70, meaning that

\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100

By the same logic, we work with the marks of the boys alone: we know the average:

\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62

And we deduce the sum of the marks for the boys:

b_1+b_2+\ldots+b_{20}=1240

Which implies that the sum of the marks of the girls is 2100-1240=860

And finally, the mean for the girls alone is

\dfrac{860}{10}=86

6 0
3 years ago
The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

6 0
3 years ago
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