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Alex Ar [27]
3 years ago
14

Can someone help me on 6 please

Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

Answer:

1) Inequality: 110x>150+85x

2) Solution: x>6, then Nadia would need to sell more than 6 ads per week in order for Choice A to be the better choice,


<u>Solution:</u>

Be x the number of ads Nadia sells

A) Choice A: $110 for each ad she sells. She would earn:

Ea=110x

B) Choice B: A weekly salary of $150, plus $85 for each ad she sells. She would earn:

Eb=150+85x

1) Write an inequality to determine the number of ads Nadia would need to seel per week in order for Choice A to be the better choice:

Ea>Eb

110x>150+85x

2) Solution

Solving for x: Subtracting 85x both sides of the equation:

110x-85x>150+85x-85x

Subtracting:

25x>150

Dividing both sides of the equation by 25:

25x/25>150/25

Dividing:

x>6

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P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

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P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

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P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

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P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

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Now substituting (2), (3) , (4) in (1), we get

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P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

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