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ELEN [110]
3 years ago
13

Given the general form of the sinusoidal function, y = AsinB(x - C) + D, match the following items.

Mathematics
1 answer:
Jet001 [13]3 years ago
6 0

Answer:

\Delta y = A (Amplitude) (Correct answer: 1)

\omega = B (Angular frequency) (Correct answer: 2)

x_{o} = C (Phase shift) (Correct answer: 3)

y_{o} = D (Vertical shift) (Correct answer: 4)

\frac{2\pi}{\omega} = \frac{2\pi}{B} (Period) (Correct answer: 5)

Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o} (1)

Where:

\Delta y - Amplitude.

\omega - Angular frequency.

x_{o} - Phase shift.

y_{o} - Vertical shift.

x - Independent variable.

y - Dependent variable.

In addition, we know that the period associated with the sinusoidal function (T) is:

T = \frac{2\pi}{\omega}

By direct comparison, we get the following conclusions:

\Delta y = A (Amplitude) (Correct answer: 1)

\omega = B (Angular frequency) (Correct answer: 2)

x_{o} = C (Phase shift) (Correct answer: 3)

y_{o} = D (Vertical shift) (Correct answer: 4)

\frac{2\pi}{\omega} = \frac{2\pi}{B} (Period) (Correct answer: 5)

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Zinaida [17]

Answer:

D.

C.

Step-by-step explanation:

For the first question, you just need to think about what plus 1/2, or 2/4, equals 3/4. This would be D. or 1/4 because 1/4 + 2/4 = 3/4

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5 0
3 years ago
Find the exact value of cot 330° in simplest form with a rational denominator.
Hoochie [10]

Answer:

\cot 330^{\circ} = -\sqrt{3}

Step-by-step explanation:

The cotangent function can be rewritten by trigonometric relations, that is:

\cot 330^{\circ} = \frac{1}{\tan 330^{\circ}} = \frac{\cos 330^{\circ}}{\sin 330^{\circ}} (1)

By taking approach the periodicity properties of the cosine and sine function (both functions have a period of 360°), we use the following equivalencies:

\sin 330^{\circ} = \sin (-30^{\circ}) = -\sin 30^{\circ} (2)

\cos 330^{\circ} = \cos (-30^{\circ}) = \cos 30^{\circ} (3)

By (2) and (3) in (1), we have following expression:

\cot 330^{\circ} = -\frac{\cos 30^{\circ}}{\sin 30^{\circ}}

If we know that \sin 30^{\circ} = \frac{1}{2} and \cos 30^{\circ} = \frac{\sqrt{3}}{2}, then the result of the trigonometric expression is:

\cot 330^{\circ} = -\frac{\frac{\sqrt{3}}{2} }{\frac{1}{2} }

\cot 330^{\circ} = -\sqrt{3}

6 0
3 years ago
Can someone help me with this step by step? will award brainliest :) thank you sm!!
mestny [16]

I'm not this high in maths but I think it's -10 I don't know but I worked it out

5 0
4 years ago
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jekas [21]

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a is 1

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Step-by-step explanation:

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frez [133]

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glad to help any time





5 0
3 years ago
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