All categories

3 years ago

A target is shielded from a radioactive sample by a sheet of metal. What kind of radiation can pass through the sheet of metal

Chemistry

2 answers:

-BARSIC- [3]3 years ago

8 0

Answer:

Gamma Rays Only

Explanation:

Right on edge.

White raven [17]3 years ago

4 0

Answer:

gamma rays only is the correct answer.

Explanation:

Every radiation has different penetrating power to penetrate in materials and the flow of particles through a material is called penetration power.

Penetrating power of the gamma rays is very high because it has no mass and charges that the reason it can travel far in the air than beta particles and alpha particles.

Alpha particles can be blocked by paper and beta particles can easily passes through paper but it cannot pass through aluminum sheet whereas gamma particles are hardest to blocked, gamma particles can be blocked by heavy shielding.

Thus the radiation can pass through sheet of metak and hit the target is only gamma rays.

You might be interested in

a solution has a volume of 2.0L and contains 36.0 g of glucose. If the molar mass of glucose is 180 g/mol, what is the morality

lilavasa [31]

Find moles:
36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose 

find molarity: 
0.200 moles of glucose / 2 litres = 0.100 Molar solution

3 0

4 years ago

How many grams do 1.5 x 1026 atoms of magnesium weigh?

LUCKY_DIMON [66]

Answer:

0.3

Explanation:

if I'm wrong don't mark it against me

4 0

3 years ago

Which inquiry skill is based on identifying common features?

expeople1 [14]

Classify is the answer hope this helps :)

3 0

3 years ago

The depletion of ozone (O3) in the stratosphere has been a matter of great concern among scientists in recent years. It is belie

Deffense [45]

Answer: Nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

Explanation:

To calculate the number of moles, we use the equation

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For ozone:

Given mass of ozone = 0.827 g

Molar mass of ozone = 48 g/mol

Putting values in above equation, we get:

$\text{Moles of ozone}=\frac{0.827g}{48g/mol}=0.0172mol$

For nitric oxide:

Given mass of nitric oxide = 0.635 g

Molar mass of nitric oxide = 30.01 g/mol

Putting values in above equation, we get:

$\text{Moles of nitric oxide}=\frac{0.635g}{30.01g/mol}=0.0211mol$

For the given chemical equation:

$O_3+NO\rightarrow O_2+NO_2$

By Stoichiometry of the reaction:

1 mole of ozone reacts with 1 mole of nitric oxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitric oxide

As, given amount of nitric oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ozone is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (nitric oxide) left = 0.0211 - 0.0172 = 0.0039 moles

By Stoichiometry of the reaction:

1 mole of ozone produces 1 mole of nitrogen dioxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitrogen dioxide

Now, calculating the mass of nitrogen dioxide from equation 1, we get:

Molar mass of nitrogen dioxide = 46 g/mol

Moles of nitrogen dioxide = 0.0172 moles

Putting values in equation 1, we get:

$0.0172mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.7912g$

Hence, nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

8 0

4 years ago

PLEASE HELP

Marysya12 [62]

Answer:

Military

Explanation:

I may be wrong but military seems most likely

6 0

3 years ago

Read 2 more answers