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3 years ago

Started: Feb 22 at 92

Chemistry

1 answer:

aliina [53]3 years ago

7 0

Answer:

1272 pound

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 38 psi

Area (A) = 12 cm by 18 cm

Force (F) =?

Next, we shall determine the area. This can be obtained as follow:

Area (A) = 12 cm by 18 cm

A = 216 cm²

Next, we shall convert 216 cm² to square inch (in²). This can be obtained as follow:

1 cm² = 0.155 in²

Therefore,

216 cm² = 216 cm² × 0.155 in² / 1 cm

216 cm² = 33.48 in²

Finally, we shall determine the force exerted. This can be obtained as follow:

Pressure (P) = 38 psi = 38 lbf/in²

Area (A) = 33.48 in²

Force (F) =?

P = F/A

38 = F / 33.48

Cross multiply

F = 38 × 33.48

F = 1272 pound

Thus, the force exerted is 1272 pound

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3 years ago

1.Which statement best describes scientific laws

gtnhenbr [62]

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3 years ago

Balance the following chemical equation

ratelena [41]

Answer:

Explanation:

4). Ca(NO₃)₂ + Na₂SO₄ → CaSO₄ + 2Na(NO₃)₂

This question is incorrect.

Since, the final product by reacting Na⁺⁺ and NO₃⁻⁻ is NaNO₃

Correct equation will be,

Ca(NO₃)₂ + Na₂SO₄ → CaSO₄ + 2NaNO₃

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5). Ni(NO₃)₂ + KI → NiI + 2K(NO₃)₂

Correct equation will be,

Ni(NO₃)₂ + KI → NiI₂ + 2KNO₃

[Since final product by reacting Ni⁺⁺ and I⁻ is NiI₂]

Balanced form of this equation will be,

Ni(NO₃)₂ + 2KI → NiI₂ + 2KNO₃

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Correct form of the equation will be

Ni(NO₃)₂ + KOH → Ni(OH)₂ + KNO₃

[Since reaction of Ni⁺⁺ and OH⁻ gives Ni(OH)₂ and the reaction of K⁺ and NO₃⁻ gives KNO₃]

Now balancing this equation,

Ni(NO₃)₂ + KOH → Ni(OH)₂ + 2KNO₃

↓

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4 years ago

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lisabon 2012 [21]

Answer: C) Bent or angular, polar
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3 0

3 years ago

A student finds two unlabeled flasks of clear liquids. One is believed to be 0.1 m nacl and the other to be 0.1 m naclo3. What i

KonstantinChe [14]

Answer:

Add AgNO₃ solution to both unlabeled flasks: based on solubility rules, you can predict that when you add AgNO₃ to the NaCl solution, you will obtain AgCl precipitate, while no precipitate will be formed from the NaClO₃ solution.

Explanation:

1. Adding AgNO₃ to NaCl solution:

AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃ (aq)

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AgNO₃ (aq) + NaClO₃ (aq) → AgClO₃ (aq) + NaNO₃ (aq)

3. Relevant solubility rules for the problem.

Although most salts containing Cl⁻ are soluble, AgCl is a remarkable exception and is insoluble.

All chlorates are soluble, so AgClO₃ is soluble.

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Hence, when you add AgNO₃ to the NaCl solution the AgCl formed will precipitate, and when you add the same salt (AgNO₃) to the AgClO₃ solution both formed salts AgClO₃ and NaNO₃ are soluble.

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