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Ilya [14]
3 years ago
7

Which correctly describes the behavior of the graph of y=5 in the xy-plane?

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

the answer is A)

Step-by-step explanation:

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A balloon is released from a height of 10 feet. The balloon climbs an additional 70% of its previous height as each minute passe
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The initial height of the balloon is 10 feet which then increases by 70% to (10 ×1.7) = 17 feet, then to (17 × 1.7) =28.9 feet, and so fourth if the rate of increase is kept constant. Therefore, forming a geometric sequence such that to get any term in the sequence we use the formula ar∧(n-1), where a is the first term, r is the common ratio, and n is the term in the sequence. In this case a is 10 and r= 1.7 , to get the height in the fourth minute it means n =5 (for the first term there is 0 minutes, such that for 0 minutes n= 1)
Thus, 10 × 1.7 ∧ 4 = 83.521 feet.
Therefore, the answer is 83.521 feet
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9 percent won the game
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Compare 3.6 to the square root of 12
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. Adult tickets to a play cost $22. Tickets for children cost $15. Tickets for a group of
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Which expression is equivalent to 4√24x∧6y÷ 128x∧4y∧5
LenKa [72]

Answer:

Option D.  \sqrt[4]{\frac{3x^{2}}{2y}}

Step-by-step explanation:

\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}

\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}

= \sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}

= \sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}

= \sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}

= \sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}

= \frac{y^{-1}}{2}\sqrt[4]{3x^{2}}

= \sqrt[4]{\frac{3x^{2}}{2y}}

Option D. \sqrt[4]{\frac{3x^{2}}{2y}}  is the correct answer.

5 0
3 years ago
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