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olga2289 [7]
3 years ago
7

What is the standard form of the equation of a circle given by x2 + y2 – 18x + 8y + 5 = 0?

Mathematics
2 answers:
mario62 [17]3 years ago
7 0
The guy who answered is right but the radius is 92
avanturin [10]3 years ago
3 0
X²-18x+81 + y²+8y+16 = -5+81+16=92
(x-9)² + (y+4)² = (2✓23)²

circle centered at (9,-4) with radius 2✓23
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What does 3y-y equal?
Novosadov [1.4K]

Answer:

2y

Step-by-step explanation:

You need to subtract the coefficients to get the answer.

Let's look at the equation...

3y-y

The coefficient is 3 and 1

So, you do 3-1

You get 2

So...

3y-y=2y

4 0
3 years ago
Write the following question expression in simplest binomial form 4(3x-2)-2(4x+5)
Oduvanchick [21]
4(3x-2)-2(4x+5) 

12x-8-8x-10
 

(12x-8x)+(-8-10)
 

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Please do question 5 im giving out brainlyist or something like that :)
jonny [76]

I would say none

because each one equals to 24 students, when it says there are 24 students in each are class. so you would need to do 24 * 5 to get the amount of students.

5 0
3 years ago
Read 2 more answers
37 + 15r > or equal to 127, what is the answer?
Tpy6a [65]

Answer:

r ≥ 6

Step-by-step explanation:

37+15r ≥ 127

-37           -37          37 cancels and you're left with 15r

    15r ≥ 90

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4 0
3 years ago
Explain 15 is not a prime factor
MissTica

<em>1</em><em>5</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>a</em><em> </em><em>prime</em><em> </em><em>factor</em><em> </em><em>as</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>1</em><em>,</em><em>3</em><em>,</em><em>5</em><em> </em><em>and</em><em> </em><em>1</em><em>5</em><em>.</em>

<em>Additional</em><em> </em><em>information</em><em>:</em>

<em>Prime</em><em> </em><em>numbers</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>only</em><em> </em><em>be</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>itself</em><em> </em><em>.</em><em>for</em><em> </em><em>instance</em><em>:</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>5</em><em>,</em><em>7</em><em> </em><em>,</em><em>1</em><em>1</em><em>,</em><em>1</em><em>3</em><em> </em><em>etc</em><em>.</em>

<em>Composite</em><em> </em><em>number</em><em> </em><em>s</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>also</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>other</em><em> </em><em>numbers</em><em>,</em><em>For</em><em> </em><em>instance</em><em>:</em><em> </em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>1</em><em>0</em><em> </em><em>etc</em>

<em>Hope</em><em> </em><em>it </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
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