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DENIUS [597]
3 years ago
6

I still don't know what I'm supposed to do here..

Mathematics
1 answer:
Burka [1]3 years ago
6 0

multiply the radius by 2

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Express 13,040,000 in scientific notation
ser-zykov [4K]
1.304 *  10^{7}
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3 years ago
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A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

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3 years ago
M=x^3+y^2-6(x-y)-2021
bagirrra123 [75]

Answer:

Step-by-step explanation:

m=x^3+y^2-6(x-y)-2021

distribute: 6x-6y

now you have m=x^3 + y^2 - 6x - 6y - 2021

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The answer the answer is appropriately 40
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