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Alexxandr [17]
3 years ago
15

Two drivers are 420 miles away from each other when they started moving towards each other. They meet after 4 hours. What is the

speed of the first car, if the second car's speed is 45 mph?

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0
The first car is going 60 miles per hour because if the second car is going at 45 mph, after 4 hours it has already travelled 180 miles. In order for both cars to meet from a total distance of 420 miles, the first car has to travel 420 miles - 180 miles meaning that the first car travelled 240 miles. When you look back at how it took 4 hours for both cars to meet each other, this also means that the first car traveled 4 hours. So the car traveled 240 miles in 4 hours meaning that it went 240miles/4hours or 60mph.

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What is a segment in a circle
Art [367]

Answer:

A segment is a region bounded by a chord of a circle and the intercepted arc of the circle. A segment with an intercepted arc less than a semicircle is called a minor segment.

Step-by-step explanation:

3 0
3 years ago
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Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
4 years ago
PLEASE HELP, I don’t know how to do this...like at all
Svet_ta [14]

Answer:

arc ? = 255°

Step-by-step explanation:

arc DB = 180° - 75° = 105°

arc ? = 360° - 105° = 255°

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4900 is the answer :)
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How do you work this out in confused?
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I think you either need to double 35 or use a protractor. Hope this is helpful!
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