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3 years ago

How to multiply and divide

Mathematics

1 answer:

Vikentia [17]3 years ago

8 0

Answer:

Multiplication...

Multiplication is just like adding a number to itself multiple times

For example: 3x3 is the same as 3+3+3

Division...

Division is basically splitting up a number between amother lower number, (it might be pretty difficult if you don’t know how to multiply though...)

Start by Rephrasing/re-ordering the equation (9/3 looks like 3*[?] =9)

1) Figure out what Factors equal 9 (by looking at a multiplication table or by adding up like described earlier)

2) You have your answer

(this took way too long to write and you’re probably an idiot if you’re actually in middle school...smh) I can write a different answer if you meant long division, or something else

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Kyle is another carpenter. He has three measuring sticks. The lengths of

Lina20 [59]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

Factor the expression.

grigory [225]

Hey!

First, let's write the problem,
$4r^2-64$
Factor out the common term, which is 4,
$=4\left(r^2-16\right)$
Then, let's factor this part: $r^2-16$
We are going to factor it using the difference of squares rule.
$=\left(r+4\right)\left(r-4\right)$
Our final factored answer would be,
$=4\left(r+4\right)\left(r-4\right)$

Thanks!
-TetraFish

8 0

3 years ago

Read 2 more answers

Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$