Question

If you know please help me

Answer 1

Average rate of change of the function $=\frac{75}{2}$

Solution:

Given function: $f(x)=5(2)^{x}$ from x = 1 to x = 5

Substitute x = 1 and x = 5 in f(x).

$f(1)=5(2)^{1}=10$

$f(5)=5(2)^{5}=160$

Let us find the average rate of change of the function.

Average rate of change

                      $=\frac{f(b)-f(a)}{b-a}$

Here a = 1 and b = 5.

                     $=\frac{f(5)-f(1)}{5-1}$

Substitute f(5) and f(1).

                     $=\frac{160-10}{4}$

                     $=\frac{150}{4}$

                     $=\frac{75}{2}$

Average rate of change of the function $=\frac{75}{2}$