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ANTONII [103]
3 years ago
7

If you know please help me

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

Average rate of change of the function =\frac{75}{2}

Solution:

Given function: f(x)=5(2)^{x} from x = 1 to x = 5

Substitute x = 1 and x = 5 in f(x).

f(1)=5(2)^{1}=10

f(5)=5(2)^{5}=160

Let us find the average rate of change of the function.

Average rate of change

                      $=\frac{f(b)-f(a)}{b-a}

Here a = 1 and b = 5.

                     $=\frac{f(5)-f(1)}{5-1}

Substitute f(5) and f(1).

                     $=\frac{160-10}{4}

                     $=\frac{150}{4}

                     $=\frac{75}{2}

Average rate of change of the function =\frac{75}{2}

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To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 45.5 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 45.5 is 100%, so we can write it down as 45.5=100%.

4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.

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6. Now we just have to solve the simple equation, and we will get the solution we are looking for.


7. Solution for what is 6.81% of 45.5


45.5/x=100/6.81

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45.5=14.684287812041*x       - we divide both sides of the equation by (14.684287812041) to get x

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