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ANTONII [103]
4 years ago
7

If you know please help me

Mathematics
1 answer:
MrRa [10]4 years ago
4 0

Average rate of change of the function =\frac{75}{2}

Solution:

Given function: f(x)=5(2)^{x} from x = 1 to x = 5

Substitute x = 1 and x = 5 in f(x).

f(1)=5(2)^{1}=10

f(5)=5(2)^{5}=160

Let us find the average rate of change of the function.

Average rate of change

                      $=\frac{f(b)-f(a)}{b-a}

Here a = 1 and b = 5.

                     $=\frac{f(5)-f(1)}{5-1}

Substitute f(5) and f(1).

                     $=\frac{160-10}{4}

                     $=\frac{150}{4}

                     $=\frac{75}{2}

Average rate of change of the function =\frac{75}{2}

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