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2 years ago

30 POINTS i need helpppp

Mathematics

1 answer:

nika2105 [10]2 years ago

5 0

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WILL MARK BRAINLIEST!!!

hoa [83]

9514 1404 393

Answer:

a = 17
∠ABC = 78°

Step-by-step explanation:

The marked angles form a linear pair, so have a sum of 180°.

(4a +10) +(6a) = 180

10a = 170 . . . . . . . . . . subtract 10

a = 17 . . . . . . . . . . . . . divide by 10

Then the measure of angle ABC is ...

∠ABC = 4a +10 = 4(17) +10 = 68 +10 . . . . . substitute 17 for 'a'

∠ABC = 78°

5 0

2 years ago

What is another way to write the absolute inequality |p|<12?

GaryK [48]

Answer:

$-12$

Step-by-step explanation:

$\left|p\right|$

The interval notation is (-12, 12).

$-12$

7 0

2 years ago

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

marissa [1.9K]

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = $\frac{\pi}{2}$ square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

$A = \frac{1}{2} r^2 \theta$

Where, A = area

r = radius = 3

$\theta = \frac{1}{9}\pi$

Substituting values in the formula, we have:

$A = \frac{1}{2}*3^2* \frac{1}{9}\pi$

$A = \frac{1}{2}*9* \frac{1}{9}\pi$

$A = 4.5 * \frac{1}{9}\pi$

$A = \frac{\pi}{2}$

The area of the sector = $\frac{\pi}{2}$ square units

8 0

3 years ago

What is the slope of the line through (1, -1) and (5. – 7)?

Vladimir [108]

Answer:

-3/2

Step-by-step explanation:

Given two points, we can find the slope by

m = (y2-y1)/(x2-x1)

= (-7 - -1)/ (5-1)

= (-7+1)/(5-1)

= -6/4

= -3/2

6 0

2 years ago

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I forgot someone help me plz

o-na [289]

Write the conjugates of them then FOIL both the top and bottom, then factor

5 0

2 years ago

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