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AnnyKZ [126]
3 years ago
12

A pair of equations is shown below.

Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0
3x − y = 9
y = −2x + 11

3x − (−2x + 11) = 9
3x + 2x - 11 = 9
5x = 9 + 11
5x = 20
x = 4

y = −2x + 11 = -2*4+11 = 3

(4, 3)



viktelen [127]3 years ago
7 0

Answer:

Hence, the two equations intersect at:

(4,3)

Step-by-step explanation:

We are given:

A pair of equations:

3x − y = 9

y = −2x + 11

now, on graphing these equations.

as we can clearly see from the graph the two lines intersect at (4,3)

Hence, the two equations intersect at:

(4,3)

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There are 400 students, and 100 buses, so number of student in each bus= 400/100

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6 0
3 years ago
Find the probability of obtaining exactly 3 heads when flipping 4 coins.
monitta
The answer is 5/16 because in total there are 16 possibilities when tossing a coin 4 times.
8 0
3 years ago
Help please. Sort the numbers.
jasenka [17]

Answer:

1 = The Value of the expression is 10 for x = 3 and y = 2

2 = The Value of the expression is 10 for x = 3 and y = 2

3 = The Value of the expression is 10 for x = 2 and y = 3

4 = The Value of the expression is 10 for x = 2 and y = 3

5 = The Value of the expression is 10 for x = 2 and y = 3

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8 0
3 years ago
Solve for x<br><br> 4 to 6 = x to 18
levacccp [35]
4:6 x:18

Lets solve for x

Cross multiply

4*18 = 72
6*x = 6x

6x = 72
6x/6 = 72/6
x = 12

Answer: x = 12
3 0
3 years ago
If The 3rd term of an A.S is and 5th term is . What is an A.P?​
Bad White [126]

Question:

If The 3rd term of an A.S  23 is and 5th term is 15 .P What is an A.?​

Answer:

A.P is   31, 27, 23 ,19, 15, 11, 7, 3

Step-by-step explanation:

Given:

3rd term =  23

5th term =  15

To Find:

The arithmetic Progression = ?

Solution:

Let

a_1 be the first term and d be difference

Then the arithmetic progression will be ,

a_1 , (a_1+d),(a_1 +2d),......(a_1+(n-1)d)

From the question ,

third term = 13

(a_1 +2d) = 23-------------(1)

Similarly

(a_1 +4d) = 15-----------------(2)

Subtracting (1) from  (2) we get

-2d =8

d = \frac{8}{2}

d = -4

Substituting d = 4 in equation 1, we get

(a_1 +2(-4)) = 23

(a_1 -8) = 23

a_1 = 23 +8

a_1 = 31

a_1 , (a_1+d),(a_1 +2d),......(a_1+(n-1)d)

=  31 ,(31 +(-4)) ,(31 +2(-4)), (31+3(-4)).........

=>  31, 27, 23 , 19, 15, 11,7,3

3 0
4 years ago
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