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2 years ago

What are the solutions to the equation? n^2−8n+16=25

Mathematics

1 answer:

Monica [59]2 years ago

7 0

1. You have the quadratic equation <span>n^2−8n+16=25 and to solve it, you must apply the proccedure below:
</span><span>
n^2−8n+16=25
</span><span>n^2−8n+16-25=0
</span><span>n^2−8n-9=0

2. When you factorize </span> n^2−8n-9=0<span>, you obtain the following:

(n-9)(n+1)=0

3. Therefore the values of n1 and n2 are shown below:

n1=9
n2=-1</span>

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Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1

ElenaW [278]

<h2>Hello!</h2>

The answers are:

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{6}{7}$ and $1\frac{5}{7}$

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

$\frac{5}{6}$ and $\frac{10}{12}$

We have that:

$\frac{10}{12}=\frac{5}{6}$

So, we have that the pairs of numbers

$\frac{5}{6}$

and

$\frac{5}{6}$

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

$\frac{6}{7}$ and $1\frac{5}{7}$

We have that:

$1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}$

So, we have that the pair of numbers

$\frac{6}{7}$

and

$\frac{12}{7}$

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

$\frac{3}{2},\frac{2}{3}$

and

$3\frac{1}{2},4\frac{4}{4}$

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{6}{7}$ and $1\frac{5}{7}$

Have a nice day!

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