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3 years ago

8

Allyson has a collection of 26 mugs. When packing to move, she put the same number of mugs in each of the first 4 boxes and 2 mu

gs in the last box. What is the number of mugs in each of the first four boxes?

1 answer:

Grace [21]3 years ago

5 0

Answer:

6 mugs

Step-by-step explanation:

6*4=24

add the remainder 2 to get 26,

since its just asking for the 4 boxes the answer is 6

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Solve for x round to the nearest tenth

lidiya [134]

Answer:

47.0

Step-by-step explanation:

In this right angle triangle, we are faced with a challenge of two sides. The opposite side and the adjacent side, hence the tangent is used.

Where it is the opposite side and hypothenus side, the sine is used and when it is the hypothenus side and adjacent side, the cosine is used.

Hence, we have tan62°=x/25

We cross multiply, to have

25(tan 62°)= x

x = 47.01816

In rounding up numbers, number 1 to 4 will be rounded up to zero, while numbers 5 to 9 will be rounded up to 1.

Rounding up 47.01816 to the nearest tenth. The tenth value is the figure is 0, before it we have 1, which is to hundredth. 1 will be rounded up to zero.

So we have 47.0

3 0

3 years ago

In the diagram, polygon ABCD is flipped over a line of reflection to make a polygon with vertices at A′, B′, C′, and D′. Points

Hunter-Best [27]

<span>when flipped over a line of reflection the lengths are still the same the point to the line of reflection is the same length as the line of reflection to the reflected position the distance from the original point to the reflected point is twice the distance from the original point to the line of reflection. </span>

8 0

2 years ago

Read 2 more answers

On a coordinate plane, a parabola opens up. Solid circles appear on the parabola at (negative 4, 14), (negative 3, 9. 5), (negat

umka2103 [35]

The rate of change for the interval between 2 and 6 on the x-axis is 3.

Given

On a coordinate plane, a parabola opens up.

Solid circles appear on the parabola at (negative 4, 14), (negative 3, 9. 5), (negative 2, 6), (0, 2), (1, 1. 5), (2, 2), (4, 6), (5, 9. 5), (6, 14).

<h3>What is the rate of change?</h3>

A rate of change defines how one quantity changes in relation to another quantity.

The rate of change for the interval between 2 and 6 on the x-axis is;

$\rm Rate \ of \ change =\dfrac{2-14}{2-6}\\\\Rate \ of \ change =\dfrac{-12}{-4}\\\\Rate \ of \ change =3$

Hence, the rate of change for the interval between 2 and 6 on the x-axis is 3.

To know more about Parabola click the link given below.

brainly.com/question/16549411

8 0

2 years ago

Please help will mark brainly

yawa3891 [41]

Answer:

a. 2

Step-by-step explanation:

1/6 multiplied by 2 is 2/6

hope this helps :)

5 0

3 years ago

The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x

RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

P(a < X < b) = $\int_{a}^{b} \frac{2}{x^{3}} dx$ = $2\int_{a}^{b} x^{-3} dx$

= $2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx$ { Because $\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a$ }

= $2[ \frac{x^{-2} }{-2}]^{b}_a$ = $\frac{2}{-2} [ x^{-2} ]^{b}_a$

= $-1 [ b^{-2} - a^{-2} ]$ = $\frac{1}{a^{2} } - \frac{1}{b^{2} }$

a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }

Comparing with general probability we get,

P(1 < X < 5) = $\frac{1}{1^{2} } - \frac{1}{5^{2} }$ = $1 - \frac{1}{25}$ = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/ $8^{2}$ - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = $\frac{1}{6^{2} } - \frac{1}{10^{2} }$ = $\frac{1}{36} - \frac{1}{100 }$ = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

= $(\frac{1}{1^{2} } - \frac{1}{6^{2} })$ + (1/ $10^{2}$ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

⇒ P(1 < X < x) = 0.75

⇒ $\frac{1}{1^{2} } - \frac{1}{x^{2} }$ = 0.75

⇒ $\frac{1} {x^{2} }$ = 1 - 0.75 = 0.25

⇒ $x^{2}$ = $\frac{1}{0.25}$ ⇒ $x^{2}$ = 4 ⇒ x = $2$

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0

2 years ago