15, if you plot the points, then seperate the x and y into two seperate lines, you can create a 3,4,5 triangle to find the distance between the points.
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Standard formula for arithmetic sequence:
an = a0 + d(n-1)
if we use the two terms given, setting a12 as starting term and a45 as the end term an.
170 = 38 + 33d
170 - 38 = 33d
132 = 33d
132/33 = d
This is the common difference, use it to find the first term.
38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0
The starting term is -6
Sum of 5 times z and 4 divided by two is 7.
Answer:
Step-by-step explanation:
A(3,-2) ; B(6,-2)
![AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%286-3%29%5E%7B2%7D%2B%28-2-%5B-2%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B3%5E%7B2%7D%2B%28-2%2B2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%2B0%7D%3D%5Csqrt%7B9%7D%5C%5C%5C%5C)
AB = 3 units
B(6,-2) ; C(6,5)
![BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B%286-6%29%5E%7B2%7D%2B%285-%5B-2%5D%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B0%2B%285%2B2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%287%29%5E%7B2%7D%7D%5C%5C)
BC = 7 units
Area of rectangle = length * width
= AB * BC
= 3 * 7
= 21 square units
