Answer:
49, 17, 4, 18
Step-by-step explanation:
![6 x^{3}](https://tex.z-dn.net/?f=6%20x%5E%7B3%7D%20)
+ 3x + 5
-
![2x^{2}](https://tex.z-dn.net/?f=%202x%5E%7B2%7D%20)
+ 6x + 5
-----------------------------------------
4x - 3 + 0
Answer:
c, e, f, and i
Step-by-step explanation:
a. is bounded above at y = 1 and below at y = 0
b. is unbounded both above and below
c. is bounded below at y = 0 and unbounded above
d. is unbounded both above and below
e. is bounded below at y = 0 and unbounded above
f. is bounded below at y = 0 and unbounded above
g. is bounded below at y = 0 and bounded above at y = 1
h. is unbounded both above and below
i. is bounded below at y = 0 and unbounded above
j. is unbounded both above and below
The effective annual interest rate is:
i = (1 + 0.064/12)^12 - 1 = 0.066
In year 1: the interest is $613.80 (multiple $9300 by 0.066)
In year 2: the interest is $654.31 (add interest from year 1 to $9300 and multiply by 0.066)
In year 3: the interest is $656.98 (do the same as year 2)
In year 4: the interest is $657.16
The total interest is: $2582.25
The present worth of this amount is:
P = 2582.23 / (1 + 0.066)^4 = $1999.72
The answer is $1999.72.
Answer:
1/2
Step-by-step explanation:
We first find the least common multiple, which is 6. Therefore, we can multiply 1/3 x 2/2 (since 2/2 is equal to one and won't change the final amount) and get 2/6. 2/6+1/6=3/6, or 1/2.