All categories

3 years ago

Simplify the expression 9x + 7 – x + 3

Mathematics

2 answers:

Alex787 [66]3 years ago

6 0

$\huge{\boxed{ \tt{Solution :- }}}$

<h3>Given :</h3>

$\sf {9x+7-x+3}$

$\sf {Simplify\:the\:expression.}$

Now we solving it :

$\sf{ : \implies{9x + 7 -x + 3}} \\ \\ \bf{By \:combining \: in \: like\:terms :} \\ \\ \sf{ : \implies{9x - x + 7 + 3 \: \: \: }} \\ \\ : \implies{\boxed {\tt{8x +10}}}$

$\bf{\therefore{The\:answer\: is\:8x +10.}}$

$\rule {307}{2}$

Sphinxa [80]3 years ago

5 0

Answer:

8x + 10

Step-by-step explanation:

combine 9x and -x to get 8x

combine 7 and 3 to get 10

You might be interested in

What does x2 + y2 equal.

Yuri [45]

That’s the equation for the radius of a circle, it would equal r2

5 0

2 years ago

It takes two hours for two machines to manufacture 10000 parts. If machine #1 can do the job in one hour less than machine #2, h

elena-14-01-66 [18.8K]

Answer:

Time machine one = 3.56

Time machine two = 4.56

Step-by-step explanation:

Let machine 2 do the job in x hours

Let machine 1 do the job in x - 1 hours.

The general formula for this problem is

Time = A*B/(A + B)

Givens

Time = 2 hours

B = x hours alone

A = x - 1 hours alone.

#################

x *( x - 1)

======= = 2

(x + x - 1)

(x^2 - x)/(2x - 1) = 2

x^2 - x = 2(2x - 1)

x^2 - x = 4x - 2

x^2 - 5x + 2 = 0

a = 1

b = - 5

c = 2

This gives 2 roots

x = 4.56

x = 0.43

The second root will not work because when 1 is subtracted from 0.43 the time give will be minus, which won't work.

Time for machine 2 is 4.56

The time for machine 1 is 3.56

Check

(A * B)/(A + B) = 2

A = 4.56

B = 3.56

Time = 4.56*3.56/(4.56 + 3.56)

Time = 16.2336/(8.12)

Time = 1.9992

The rounding error in the check comes from the rounding error in the times.

4 0

3 years ago

(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives