Please help me out here! Only B, not A.

Graph y = 3(x + 2)3 - 3 and describe the end behavior.

-BARSIC- [3]

1) The function is 3(x + 2)³ - 3

2) The end behaviour is the limits when x approaches +/- infinity.

3) Since the polynomial is of odd degree you can predict that the ends head off in opposite direction. The limits confirm that.

4) The limit when x approaches negative infinity is negative infinity, then the left end of the function heads off downward (toward - ∞).

5) The limit when x approaches positive infinity is positivie infinity, then the right end of the function heads off upward (toward + ∞).

6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.

7) x-intercepts ⇒ y = 0

⇒ 3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0


⇒ (x + 2)³ = -1 ⇒ x + 2 = 1 ⇒ x = - 1


8) y-intercepts ⇒ x = 0

y = 3(x + 2)³ - 3 = 3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 = 21


9) Critical points ⇒ first derivative = 0


i) dy / dx = 9(x + 2)² = 0


⇒ x + 2 = 0 ⇒ x = - 2


ii) second derivative: to determine where x = - 2 is a local maximum, a local minimum, or an inflection point.


y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.


Then the function does not have local minimum nor maximum, but an inflection point at x = -2.


Using all that information you can graph the function, and I attache the figure with the graph.

3 0

3 years ago

Given: JK || QP, JK congruent to PQ Prove: KQ bisects JP

Iteru [2.4K]

Answer:

Step-by-step explanation: it will because it will divide it in two given those statements

3 0

2 years ago

You paid $44 to a loan company for the use of $1,153 for 119 days, what annual rate of interest did they charge? (Assume a 360-d

Zigmanuir [339]

Answer:

Ans. A) The annual rate that the company charged was 11.996%; B) if they charged you 11.186% annual rate, you would have to pay $41.14

Step-by-step explanation:

Hi, first we have to find out what is the effective 119 days rate and then turn it into an annual rate. This is as follows.

$r(Effective119Days)=\frac{44}{1,153} x100=0.038161$

So the charged rate was 3.816% effective, 119 days, now let´s make it an annual rate.

$r(annual)=(1+0.038161)^{\frac{360}{119} } -1=0.119965$

This means that the equivalent rate to 3.816% effective 119 days ys 11.996% effective annually (or just annual).

Now, if they were to charge you 11.186% annual, you would have to make this rate effective 119 days, and then, multiply it by the principal ($1,153). Let´s change the rate first.

$r(Effective119Days)=(1+0.11186)^{\frac{119}{360} -1}=0.03568$