All categories

2 years ago

115000 and 13% =? just look at the picture

Mathematics

1 answer:

Vesna [10]2 years ago

3 0

Answer:

The family spends $14950 on clothing.

Step-by-step explanation:

Given the total income of the family is $115000.

And the family spends 13% in clothing. This means that out of hundred dollars 13 dollars go to clothing. Then how much would it go for 115000?

This can be formulated mathematically as:

13% of 115000 = $\frac{13}{100} \times 115000$

⇒ 13 × 1150 = 14950

i.e., The family spends 14950 $ on clothing.

You might be interested in

Solve: X + y = 4 -5x - 6y = -18

LiRa [457]

Answer: x = -5, y = 9

Step-by-step explanation:

The solution to the system of equations can be represented as a point.

4 0

3 years ago

Read 2 more answers

Solve: 2 + = 2. Give solutions in interval [0, 2)

Dovator [93]

$\because\cos 2x+\sin x=\sin 2x$ $\because\sin 2x=2\sin xcosx$ $\because\cos 2x=\cos ^2x-\sin ^2x$

→ Substitute cos 2x and sin 2x by their expressions

$\therefore\cos ^2x-\sin ^2+\sin x=2\sin x\cos x$

→ Subtract both sides by sin x

$\cos ^2x-\sin ^2x=2\sin xcosx-\sin x$

→ Take sin x as a common factor in the right side

$\therefore\cos ^2x-\sin ^2x=\sin x(2\cos x-1)$

From the graph, the equation has 4 solutions, the intersection points between the 2 graphs

7 0

1 year ago

Minimize Q=3x2+3y2, where x+y=6.

weeeeeb [17]

Answer:

$+(x + y) {}^{2} = 6 {}^{2} \\ x {}^{2} + 2xy + y {?}^{2} = 36$

$x {}^{2} + y {}^{2} = 36 - 2xy$

$q = 3(x {}^{2} + y {}^{2} )$

$q = 3(36 - 2xy) = 108 - 6xy$

5 0

2 years ago

Prove that the triangles shown below are similar and provide a similarity statement

Salsk061 [2.6K]

The triangles are similar because two angles have the same measurements

6 0

2 years ago

Is the point (16,20) on line ℓ?

kicyunya [14]

Answer:

YES

Step-by-step explanation:

Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.

Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.

Substitute ⁵/4 in y = kx

We would have:

y = ⁵/4x.

Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.

Let's plug in (16, 20) into y = ⁵/4x.

Thus substitute x = 16 and y = 20, we have:

[tex] 20 = \frac{5}{4}(16) [/trex]

[tex] 20 = (5)(4) [/trex]

[tex] 20 = 20 [/trex]

It makes the equation true. Therefore, the point, (16, 20) is a point on line l.

7 0

2 years ago