Answer:
The approximation is 0.2( real value is 0.19)
Step-by-step explanation:
In this question, we are to calculate the best approximation if in a pack of cards labeled 1 to 21 , the card selected is a multiple of 5
First we know that the total number of options in our sample space is 21; from 1 to 21
now let’s get the multiples of 5. we have 5,10,15 and 20
The probability of selecting a multiple of 5 is thus; 4/21 . This can be approximately be said to be 0.2 ( actual value is 0.19)
35% of 100 is 35 hope that helps
The anwser is 19 remainder 4
Answer:
a movie, m is 3
a video game, v is 5.5
Brainliest would be really appreciated. (need it to unlock chat)
Feel free to ask further questions if you feel like it.
Till then, have a nice day
Step-by-step explanation:
I 5m+2v=26
II 3m+8v=53
I 5m+2v=26 devide by 2 on both sides
5/2m+v=13 subtract 5/2m om both sides
v=13-5/2m
Now put this whole thing in the other equation II, replacing the v there
3m+8(13-5/2m)=53 just calculate it
3m+104-20m=53
-17m+104=53 subtract 53 on both sides
-17m+51=0 add 17m on both sides
51=17m devide by 17
3=m
we found m, v is easy
now put m in an equation from the start, let's take equation I here
I 5m+2v=26
5*(3)+2v=26
15+2v=26 subtract 15 on both sides
2v = 11 devide by 2
v = 5.5
So we found m and v, prices for single items. we can proof this when we put m and v into a given equation and the if it equals a true value
m & v in II
II 3m+8v=53
3*(3)+8*(5.5)=53
9+44=53
53=53
Seems legit.