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iren2701 [21]
2 years ago
14

Solve the following question

Mathematics
1 answer:
emmasim [6.3K]2 years ago
5 0

Answer:

16 and 4

Step-by-step explanation:

Let (x+y) =20 and (x-y)=12 then:

Isolate for x in each equation

   x=20-y and x=12+y

Set the equations to equal each other since the value of x should be the same for both

   20-y = 12+y

Rearrange so that y is on one side and the numbers are on the other

   8 = 2y

   y= 8/2

   y= 4

Now  substitute the y- value back into either of the original equations

   x+y= 20

   x+4 = 20

Rearrange and isolate  x

   x = 20-4

   x = 16

So the two values are 16 and 4

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