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2 years ago

Solve the following question

Mathematics

1 answer:

emmasim [6.3K]2 years ago

5 0

Answer:

16 and 4

Step-by-step explanation:

Let (x+y) =20 and (x-y)=12 then:

Isolate for x in each equation

x=20-y and x=12+y

Set the equations to equal each other since the value of x should be the same for both

20-y = 12+y

Rearrange so that y is on one side and the numbers are on the other

8 = 2y

y= 8/2

y= 4

Now substitute the y- value back into either of the original equations

x+y= 20

x+4 = 20

Rearrange and isolate x

x = 20-4

x = 16

So the two values are 16 and 4

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This type of problem is called a permutation problem, and we write Pnr for the number of ways of choosing r items from n possibilities when the order of the items matters. In this case we are choosing 3 reindeer from 4 possibilities, and the order they appear in the flying line does matter, so the answer we want is P43. The general formula is Pnr=n!(n−r)!. For the answer we are looking for we therefore have:

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