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3 years ago

Y is more than half of x

Mathematics

1 answer:

Serggg [28]3 years ago

4 0

Answer:

Step-by-step explanation:

y is more than half of x could be expressed as follows.

y > x/2

You might be interested in

D = b^2 -4ac solve for a 2/3 (x-18y) = 6y solve for x

seropon [69]

Answer:

a = $\frac{b^2-d}{4c}$

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

<u>Question 1</u>

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = $\frac{b^2-d}{4c}$

<u>Question 2</u>

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate <em>x </em>by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

7 0

3 years ago

A Lake Tahoe Community College instructor is interested in the mean number of days Lake Tahoe Community College math students ar

Vlad1618 [11]

Answer:

Step-by-step explanation:

Hello!

The population is the set of elements that you are interested in studying. In this example, the instructor wants to know the number of days Lake Tahoe Community College math students are absent from class during a quarter. To do so she will take a random sample of math students and register the number of absences of each student. Each math student is an element of the population.

Then the population is "Lake Tahoe Community College math students"

I hope it helps!

6 0

3 years ago

What Is a area with dimensions 1 unit times 1 unit

Ludmilka [50]

Area is length x width so if the dimensions are both 1,
the area is $1^{2}$

7 0

3 years ago

Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1

Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

$(x - a)^2 + (y - b)^2 = R^2$

Here we are given the equation:

$x^2 + y^2 + 10x - 1 = 0$

Completing squares, we get:

$x^2 + 10x + y^2 = 1$

Now we can add and subtract 25 to get:

$x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26$

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

3 0

2 years ago

The average number of traffic tickets issued in a city on any given day

Anton [14]

Answer:

The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by

$T(x) = -6x^2 + 84x + 37$

Where x represents the number of days after Sunday

T(x) represents the number of traffic tickets issued.

Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute x= 0

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37$

On Sunday 37 tickets were issued

Substitute x= 1

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(1)^2 + 84(1) + 37\\T(x)=115$

On Monday 115 tickets were issued

Substitute x= 2

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181$

On Tuesday 181 tickets were issued

Substitute x= 3

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(3)^2 + 84(3) + 37\\T(x)=235$

On Wednesday 235 tickets were issued

Substitute x= 4

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(4)^2 + 84(4) + 37\\T(x)=277$

On Thursday 277 tickets were issued

Substitute x= 5

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307$

On Friday 307 tickets were issued

Substitute x= 6

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325$

On Saturday 325 tickets were issued

Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

6 0

3 years ago