Subtract 5 to both sides so that the equation becomes -2x^2 + 6x - 1 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -6 ± √((6)^2 - 4(-2)(-1)) ] / ( 2(-2) )
x = [-6 ± √(36 - (8) ) ] / ( -4 )
x = [-6 ± √(28) ] / (-4)
x = [-6 ± 2*sqrt(7) ] / (-4 )
x =3/2 ± -sqrt(7)/ 2
The answers are 3/2 + sqrt(7)/2 and 3/2 - sqrt(7)/2.
Given:
Side length of base = 8
Slant height = 6
To find:
The surface area of the square pyramid.
Solution:
Surface area:
where A is the area of base
p is the perimeter of base
s is the slant height
Area of base (A) = 8 × 8
= 64
Perimeter of base(P) = 4 × 8
= 32
Substitute these in the formula:
The surface area of the square pyramid is 160 unit².
1, 10, 25, 50, and so on...
Answer:
I think its B
Step-by-step explanation:
I'm sorry if I'm wrong. I'm busy
Answer:
26cm
Step-by-step explanation:
because 2 radius equal 1 diameter