The weight average of the coordinates is -4
<h3>How to determine the
weight average?</h3>
The complete question is given as:
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. And we need to calculate the weight average
The given parameters are:
- Coordinate -6 has a weight of 3
- Coordinate 2 has a weight of 1.
The weight average is then calculated as:
Weight average = Sum of (Weigh * Coordinate)/Sum of Weights
So, we have:
Weight average = (-6 * 3 + 2 * 1)/(3 +1)
Evaluate the products
Weight average = (-18 + 2)/(3 +1)
Evaluate the sum
Weight average = -16/4
Evaluate the quotient
Weight average = -4
Hence, the weight average of the coordinates is -4
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<u>Complete question</u>
The coordinate -6 has a weight of 3 and the coordinate 2 has a weight of 1. Calculate the weight average
-14a-5=-12
+5 +5
-14a=-7
Divide -7 by -14a
a=2
Sum of three consecutive odd integers = 
The values of the three integers.
Let us assume the three consecutive odd integers to be 
, 
and 
.
As per the condition, we have
Now, collect the like terms.
Therefore, the three consecutive odd integers whose sum is are 
, 
and 
respectively.
⇢ L. H. S. = R. H. S.
Answer:
-0.125
Step-by-step explanation:
- Im learning about this , so im not really sure
Answer:
sin(x) = 5/13
cos(y) = 5/12
Therefore, sin(x) = cos(y)
Step-by-step explanation:
Trig ratios:
where 
is the angle, O is the measure of the side opposite the angle, A is the measure of the side adjacent to the angle and H is the hypotenuse, of a right triangle
We have been given the measures of the two legs, so we can find the measure of the hypotenuse by using Pythagoras' Theorem 
(where a and b are the legs and c is the hypotenuse of a right triangle)
Now we can use the trig ratios:
Therefore, sin(x) = cos(y)
