Find the measure of the exterior angle shown
1 answer:
Answer:
• exterior angle of a triangle is equal to sum of opposite interior angle
(6x-7) = (103-x) + 2x
6x-7 = 103 - x + 2x
6x-7 = 103 + x
6x - 7 - x -103 = 0
6x - x - 110 = 0
5x - 110 = 0
5x = 110
x = 110/5
x = 22
as exterior angle is (6x-7)
= 6 × 22 - 7
= 125
-> Exterior angle is 125°
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