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Gekata [30.6K]
3 years ago
9

Help me out? tysvm!!!

Mathematics
1 answer:
Sophie [7]3 years ago
3 0

Answer: 103

Step-by-step explanation:

8 x 6.5 = 52,

52 + 8 = 60 (pints in total)

there are 2 cups in 1 pint so 60 x 2 = 120

120 - 17 = 103

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Rewrite the following expression without using absolute value. I3-√4I
nataly862011 [7]

Hey there!

\mid 3-\sqrt{4} \mid

Square root of four is positive or negative 2.

\mid 3 - \pm 2 \mid

So we have:

\mid 3-2 \mid  or  \mid 3+2 \mid

Add or subtract.

\mid 1 \mid  or  \mid 5 \mid

Simplify the absolute value bars.

1 or 5

Hope this helps!

7 0
3 years ago
Read 2 more answers
Which equation would best help solve this problem? Five added to 3 times a number is equal to 8 less than 5 times the number.
vitfil [10]
\hbox{five added to 3 times a number = to 8 less than 5 times the number} \\\\ \implies \boxed{5+3x=8-5x}
4 0
4 years ago
What is the definition of symbolism?
notka56 [123]

Answer:

The use of symbols to represent ideas or qualities.

5 0
4 years ago
A survey of 1,108 employees at a software company finds that 621 employees take a bus to work and 445 employees take a train to
anastassius [24]
We know 445 employees take the train, and that 321 of these exclusively take the train. So 445 - 321 = 124 take both the train and bus.

Now, if B is the set of employees that take the bus and T the set of employees that take the train, then

n(B\cup T)=n(B)+n(T)-n(B\cap T)=621+445-124=942

where n(A) is the number of employees belonging to a general set A.

So the probability that an employee takes either the bus or train is

\dfrac{n(B\cup T)}{1108}=\dfrac{942}{1108}\approx85\%
4 0
4 years ago
what is the probability of randomly selecting a score between 1 and 2 standard deviations below the mean?
velikii [3]

Answer:

0.13591.

Step-by-step explanation:

We re asked to find the probability of randomly selecting a score between 1 and 2 standard deviations below the mean.

We know that z-score tells us that a data point is how many standard deviation above or below mean.

To solve our given problem, we need to find area between z-score of -2 and -1 that is P(-2.

We will use formula P(a to solve our given problem.

P(-2

Using normal distribution table, we will get:

P(-2

P(-2

Therefore, the probability of randomly selecting a score between 1 and 2 standard deviations below the mean would be 0.13591.

8 0
4 years ago
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