Container a holds 762 ml of ideal gas at 2.50 atm. container b holds 149 ml of ideal gas at 4.90 atm. if the gases are allowed t

Question

Airida [17]

3 years ago

12

Container a holds 762 ml of ideal gas at 2.50 atm. container b holds 149 ml of ideal gas at 4.90 atm. if the gases are allowed t

o mix together, what is the resulting pressure?

Chemistry

1 answer:

loris [4] · Answer 1 · 2022-01-12T13:06:33+03:00

<span>Boyle's Law is P1 * V1 = P2 * V2. Let's calculate the pressure of Gas A P1 = 2.5 V1 = 762 P2 = ? and V2 = 762 + 149 = 911 So P2 = P1 * V1/V2 = 2.5 * 762/ 911 = 2.091 Let's calculate the pressure of Gas B P1 = 4.9 and V1 = 149 P2 = ? and V2 = 149 + 762 = 911 So P2 = P1 * V1/V2 P2 = 4.9 * 149/911 = 0.8014 From Dalton's law the resulting pressure = 0.8014 + 2.091 = 2.892</span>