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MrRissso [65]
3 years ago
8

Why are diamonds unevenly distributed on Earth?

Chemistry
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

Why aren't diamonds found evenly distributed on Earth? Diamonds are only formed under specific conditions that involve geological processes, such as volcanic activities and plate movements. Since these conditions and processes only take place in certain areas, you can only find diamonds in these special places.

Explanation:

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A mixture of 0.682 mol of H2 and 0.440 mol of Br2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 70
ahrayia [7]

Answer: 0.294 mol of Br_2 present in the reaction vessel.

Explanation:

Initial moles of  H_2 = 0.682 mole

Initial moles of  Br_2 = 0.440 mole

Volume of container = 2.00 L

Initial concentration of H_2=\frac{moles}{volume}=\frac{0.682moles}{2.00L}=0.341M

Initial concentration of Br_2=\frac{moles}{volume}=\frac{0.440moles}{2.00L}=0.220M

equilibrium concentration of H_2=\frac{moles}{volume}=\frac{0.536mole}{2.00L}=0.268M

The given balanced equilibrium reaction is,

                            H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)

Initial conc.              0.341 M     0.220 M         0  M

At eqm. conc.    (0.341-x) M      (0.220-x) M     (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[HBr]^2}{[Br_2]\times [H_2]}

we are given : (0.341-x) = 0.268 M

x= 0.073 M

Thus equilibrium concentration of Br_2 = (0.220-x) M = (0.220-0.073) M = 0.147 M

[Br_2]=\frac{moles}{volume}\\0.147=\frac{xmole}{2.00L}\\\\x=0.294 mole

Thus there are 0.294  mol of Br_2 present in the reaction vessel.

7 0
3 years ago
How many moles are in 35.6 g of H2O
klasskru [66]

Answer:

Given

mass of H2O (m) =35.6g

molarmass (mr) = H2O ), 1x2+16=18g/mol

moles of H2O (n) =?

sln

n=m/mr

n=35.6g/18g/mol

n=1.978moles

the moles of H2O are 1.978moles

3 0
2 years ago
10. A sample of an unknown composition was tested in a laboratory. The sample could not be broken down by
damaskus [11]

Answer:

it would be an element because its an element

Explanation:

8 0
3 years ago
Read 2 more answers
Patient added a 17-g measured dose of polyethylene glycol 3350 (MIRALAX) to 180 mL of water to use as a laxative. If the volume
Sergio [31]

Answer: Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

Specific gravity of mixture = 1.01

Explanation:

The specific gravity of an object or substance is the ratio of the density of that object or substance to that of a reference substance usually water.

<em>Specific gravity = density of substance/density of water</em>

The density of a substance is the ratio of the mass of that substance to is volume.

<em>Density = Mass/volume</em>

Density of water 1.00 g/mL,  

Apparent density of ethylene glycol 3350 = mass/volume

volume of ethylene glycol = volume of mixture - volume of water

volume of ethylene glycol = 195.6 - 180) = 15.6mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

<em>mass of water =  density of water * volume of water</em>

mass of water = 1.00g/mL * 180mL = 180 g

Mass of solution = mass of substance + mass of water = (17 + 180)g = 197g

Density of mixture = mass of mixture / volume of mixture

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

specific gravity of mixture = density of mixture / density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01

8 0
3 years ago
The standard enthapy of combustion of solid urea co(nh2)2 is -632kjmol-1 at 298k​
Setler79 [48]

Answer:

The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1

Explanation:

8 0
3 years ago
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