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3 years ago

Why are diamonds unevenly distributed on Earth?

Chemistry

1 answer:

tatuchka [14]3 years ago

8 0

Answer:

Why aren't diamonds found evenly distributed on Earth? Diamonds are only formed under specific conditions that involve geological processes, such as volcanic activities and plate movements. Since these conditions and processes only take place in certain areas, you can only find diamonds in these special places.

Explanation:

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A mixture of 0.682 mol of H2 and 0.440 mol of Br2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 70

ahrayia [7]

Answer: 0.294 mol of $Br_2$ present in the reaction vessel.

Explanation:

Initial moles of $H_2$ = 0.682 mole

Initial moles of $Br_2$ = 0.440 mole

Volume of container = 2.00 L

Initial concentration of $H_2=\frac{moles}{volume}=\frac{0.682moles}{2.00L}=0.341M$

Initial concentration of $Br_2=\frac{moles}{volume}=\frac{0.440moles}{2.00L}=0.220M$

equilibrium concentration of $H_2=\frac{moles}{volume}=\frac{0.536mole}{2.00L}=0.268M$

The given balanced equilibrium reaction is,

$H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)$

Initial conc. 0.341 M 0.220 M 0 M

At eqm. conc. (0.341-x) M (0.220-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[HBr]^2}{[Br_2]\times [H_2]}$

we are given : (0.341-x) = 0.268 M

x= 0.073 M

Thus equilibrium concentration of $Br_2$ = (0.220-x) M = (0.220-0.073) M = 0.147 M

$[Br_2]=\frac{moles}{volume}\\0.147=\frac{xmole}{2.00L}\\\\x=0.294 mole$

Thus there are 0.294 mol of $Br_2$ present in the reaction vessel.

7 0

3 years ago

How many moles are in 35.6 g of H2O

klasskru [66]

Answer:

Given

mass of H2O (m) =35.6g

molarmass (mr) = H2O ), 1x2+16=18g/mol

moles of H2O (n) =?

sln

n=m/mr

n=35.6g/18g/mol

n=1.978moles

the moles of H2O are 1.978moles

3 0

2 years ago

10. A sample of an unknown composition was tested in a laboratory. The sample could not be broken down by

damaskus [11]

Answer:

it would be an element because its an element

Explanation:

8 0

3 years ago

Read 2 more answers

Patient added a 17-g measured dose of polyethylene glycol 3350 (MIRALAX) to 180 mL of water to use as a laxative. If the volume

Sergio [31]

Answer: Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

Specific gravity of mixture = 1.01

Explanation:

The specific gravity of an object or substance is the ratio of the density of that object or substance to that of a reference substance usually water.

Specific gravity = density of substance/density of water

The density of a substance is the ratio of the mass of that substance to is volume.

Density = Mass/volume

Density of water 1.00 g/mL,

Apparent density of ethylene glycol 3350 = mass/volume

volume of ethylene glycol = volume of mixture - volume of water

volume of ethylene glycol = 195.6 - 180) = 15.6mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

mass of water = density of water * volume of water

mass of water = 1.00g/mL * 180mL = 180 g

Mass of solution = mass of substance + mass of water = (17 + 180)g = 197g

Density of mixture = mass of mixture / volume of mixture

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

specific gravity of mixture = density of mixture / density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01

8 0

3 years ago

The standard enthapy of combustion of solid urea co(nh2)2 is -632kjmol-1 at 298k

Setler79 [48]

Answer:

The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1

Explanation:

8 0

3 years ago