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2 years ago

Its B i already got it

Chemistry

1 answer:

Rina8888 [55]2 years ago

4 0

Explanation:

With all the scaling up and design improvements, the flight range of the R-7 increased to an intercontinental distance from 330 kilometers for the V-2. The R-7 ended up looking oversized even next to its American contemporaries -- the Atlas and Titan ballistic missiles.

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What’s the answer to the top one? i’m not sure if i’m right tbh.

liberstina [14]

The correct answer to the top one is d

6 0

2 years ago

What are the signs that you are getting nervous 18 POINTS )

AlexFokin [52]

- hands start getting sweaty
- nail biting or perhaps shaking legs
- the feeling of being overwhelmed
- (for some people) the stomach starts to hurt

8 0

3 years ago

g Suppose a sample of an ideal gas in a container is subjected to a temperature change. A decrease in temperature will the kinet

Umnica [9.8K]

Answer:

323.15 °C

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Thus, at constant volume and number of moles, Pressure of the gas is directly proportional to the temperature of the gas.

P ∝ T

Also,

Using Charle's law

$\frac {P_1}{T_1}=\frac {P_2}{T_2}$

Given ,

P₂ = 2P₁

T₁ = 25 °C

T₂ = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

Using above equation as:

$\frac{P_1}{298.15}=\frac{2P_1}{T_2}$

$T_2=2\times 298.15\ K$

New temperature = 596.3 K

Also,

T(K) - 273.15 = T( °C)

<u>So, Temperature = 596.3 - 273.15 °C = 323.15 °C</u>

5 0

3 years ago

Based on molecular orbital theory, the bond orders of the H—H bonds in H 2 , H 2 + , and H 2 - are _________, respectively

vodka [1.7K]

Answer:

H2-1

H2+-1/2

H22- zero

Explanation:

Bond order= Bonding electrons-antibonding electrons/2

In H2, there are two bonding electrons and no antibonding electrons. In H2+ there is only one bonding electron and no antibonding electron while in H22- there are two bonding and two antibonding electrons respectively.

4 0

3 years ago

The atomic weight of a newly discovered element is 98.225 amu. it has two naturally occuring isotopes. one isotope has a mass of

Aloiza [94]

Atomic weight of an element can be calculated as follows:
average atomic weight =
(atomic weight of first isotope)(its percentage of abundance) +
(atomic weight of second isotope)(its percentage of abundance)

average atomic weight = 98.225 amu
atomic weight of first isotope = 97.780 amu
its percentage of abundance = 1 - 0.417 = 0.583
atomic weight of second isotope = ??
its percentage of abundance = 0.417

So, just substitute in the above equation to get the atomic weight of the second isotope as follows:
98.225 = (97.78)(0.583) + (mass2)(0.417)
atomic weight of second isotope = 98.847 amu

4 0

3 years ago