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Free_Kalibri [48]
3 years ago
6

what’s the domain using inequalities for this graph?

Mathematics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

-9 ≤ x < 2

Step-by-step explanation:

Domain is the set of x-values that can be inputted into function f(x).

We can see from the graph that our x-values span from -9 to 2. Since -9 is closed dot, we include it in our domain. Since -2 is open dot, it is excluded from our domain:

[-9, 2) or -9 ≤ x < 2

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What number has the same value as 14 tens
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14 tens is equal to 140. You get this by multiplying 14 and 10. So the answer to your question is 140.
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Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18
gavmur [86]

Answer:

The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be x.

And the kitten weight = \frac{x}{2} -3

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

(x)+(\frac{x}{2}-3)=18

x+\frac{x}{2} -3=18

\frac{2x+x-6}{2} =18

\frac{3x-6}{2} =18

<em>Multiplying both sides by 2 we get:</em>

<em />3x-6=36<em />

<em>Adding both sides by 6 we get:</em>

<em />3x=42<em />

<em>Dividing both sides by 3 we get:</em>

<em />x=14\ pounds.<em />

<em>The weight of cat = 14 pounds.</em>

Substituting the value of x to get the kitten's weight:

\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.

<em>The kitten's weight = 4 pounds.</em>

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

7 0
3 years ago
Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0
3 years ago
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