Let X be the score on an english test which is normally distributed with mean of 31.5 and standard deviation of 7.3
μ = 31.5 and σ =7.3
Here we have to find score that separates the top 59% from the bottom 41%
So basically we have to find here x value such that area above it is 59% and below it is 49%
This is same as finding z score such that probability below z score is 0.49 and above probability is 0.59
P(Z < z) = 0.49
Using excel function to find the z score for probability 0.49 we get
z = NORM.S.INV(0.49)
z = -0.025
It means for z score -0.025 area below it is 41% and above it is 59%
Now we will convert this z score into x value using given mean and standard deviation
x = (z* standard deviation) + mean
x = (-0.025 * 7.3) + 31.5
x = 31.6825 ~ 31.68
The score that separates the top 59% from the bottom 41% is 31.68
1500 is the rounded number to the nearest hundreth
Hello,
Angle BCH and CHJ are alternate-interior ( and have the same measure)
82+30=3n+7
==>3n=105
==>n=35
Answer:A
Step-by-step explanation: The first few square numbers are:
1
,
4
,
9
,
16
,
25
,
36
,
49
,
√
1
=
1
√
4
=
2
√
9
=
3
√
16
=
4
√
25
=
5
√
36
=
6
w
w
w
w
w
w
←
√
40
lies here
√
49
=
7
Therefore
√
40
is between
6
and
7
Write the first ratio as 11/100 and set it equal to 22/n.
since 11 x 2=22 you can multiply 100 x 2 and you'll get 200.
*Check*: 11% of 200=22
