We have to find the values of F.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.
Substitute, x = 1/2
F(1/2) + F(−1) = −1/2.
We still are not getting the required value,
therefore,
Substitute x = −1
As, F(2) +F(−1) = 0.
now we have three equations in three unknowns, which we can solve.
It turns out that:
F(2) = 3/4
F(3) = 17/12
F(4) = 47/24
and
F(5) = 99/40
Setting
g(x) = 1 − 1/x
and using
2 → 1/2
to denote
g(2) = 1/2
we see that :
x → 1 - 1/x → 1/(1-x) →xso that:
g(g(g(x))) = x.
Therefore, whatever x 6= 0, 1 we start with, we will always get three equations in the three “unknowns” F(x), F(g(x)) and F(g(g(x))).
Now solve these equations to get a formula for F(x)
As,
h(x) = (1+x)/(1−x)which satisfies
h(h(h(h(x)))) = xNow, mapping x to h(x) corresponds to rotating the circle by ninety degrees.
Answer:
Jeremy find the cost of the sneakers by solving for the values of the 10% in dollars and subtracting the dollar amount from the cost of the sneaker
Step-by-step explanation:
Step one:
given data
cost of sneakers= $60
Required
the cost of the sneaker after the two discounts
Actually, the two percents given are the discount of the sale.
the first discount is
15%= 15/100*60
=0.15*60
=$9
The second is 10% coupon
10/100*60
=0.1*60
=$6
The total discounts = 9+6= $15
The cost of the sneakers= 60-15= $45
Jeremy find the cost of the sneakers by solving for the values of the 10% in dollars and subtracting the dollar amount from the cost of the sneaker
Answer:
C
Step-by-step explanation:
Using the rule of radicals
×
⇔ 
Simplifying each radical before combining them.

=
=
×
= 3
-----------------------------------------------------------------------------

= 
=
×
= 5
---------------------------------------------------------------------------
Hence
2(3
) - 3(5
= 6
- 15
= - 9
→ C
Need more info...........
Answer:
this mean in case of multiplying exponents with same base you should add the exponent and keep base same.
example:
