Answer:
Step-by-step explanation:
Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
It is E. 25:10 simplifies to 5:2.
An = a1+d*(n-1)
a11 = 75-8*(11-1) = -5
Functions can be represented using equations, graphs and tables.
The function is given as:
When l = 1, we have:
When l = 2, we have:
When l = 3, we have:
When l = 4, we have:
Represent the above results as a table, we have:
<u>l a(l)</u>
1 0.5
2 2.0
3 4.5
4 8.0
Read more about tables and functions at:
brainly.com/question/13136492