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3 years ago

Round 3.223 to the nearest hundredth.

Mathematics

1 answer:

SOVA2 [1]3 years ago

4 0

Answer:

3.22

Step-by-step explanation:

The nearest hundred is moving one decimal point up or seeing if the final number is 5 or more. If so, It would round up into 3.23 but its a 3, so the final digit (3) disappears

If this helped please mark brainliest :)

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From 1990 to 2000, the population of Florida increased by 2.13% per year. The population (in millions) in the year 1990 was 16 E

belka [17]

Answer:

19 million

Step-by-step explanation:

So generally whenever we express a exponential function, it's in the form: $y=a(b)^x$

where a=initial value aka when x=0

in this case, b can be expressed as: $1+r$ , where r is the growth rate, which in this case is 2.13%, and expressing that as a decimal (divide by 100), r=0.0213, thus b=1.0213

This gives us the following equation: $y=16(1.0213)^x$

To kind of give you a intuitive reason as to why this makes sense, think of that 1.0213 wrapping around the previous value.

So when x=0, it's actually just 16, since any number (besides 0) to the power of 0, equals 1.

When x=1, we get: $1.0213(16)$ , which can be expressed as a 2.13% increase from year 0

When x=2, we get: $1.0213(1.0213(16))$ , which can be expressed as a 2.13% increase from year 1

when x=3, we get: $1.0213(1.0213(1.0213(16)))$ , which can be expressed as a 2.13% increase from year 2.

In other words, each year we're getting another 1.0213 to multiply by (very definition of an exponent).

So to calculate the population in 1997, we put in x=7, since it's 7 years after 1990

We get the following equation: $y=16(1.0213)^7$

Using a calculator this simplifies to approximately: $18.5436$

Rounding this to the nearest integer would yield 19, and since the values are expressed in millions, the answer would be 19 million

4 0

2 years ago

I need to find the angles of A and B. From what I know, they should be congruent, but I've been stuck for wayyyy to long.

ANTONII [103]

Answer:

Step-by-step explanation:

If I'm not mistaken, the 76 degrees means that a is equal to 76 deg. Just visually, if you were to widen that angle, similarly, a would grow just as much.

If you know that a = 76d, b = 76d as well

8 0

3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$