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iragen [17]
3 years ago
14

If a polynomial function f(x)has root -2 + square root 8 and 9 what must be a factor of f(x)

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

Step-by-step explanation:

Given that f(x) is a polynomial function.

This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.

Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)

i.e. If -2+\sqrt{8} is a root, then -2-\sqrt{8} is also a root.

(Because this only when multiplied will make coefficients rational)

So the factors of f(x) should be atleast

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

There can be other factors also but this is compulsory

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miskamm [114]

In the first diagram the value of k is 10 and in the second diagram the value of k is 15/2.

<h3>What is the triangle?</h3>

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

In the first diagram:

The sum of the 5k + 20 and 7k + 40 is 180

5k + 20 + 7k + 40 = 180

12k + 60 = 180

12k = 180 -60

12k = 120

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In the second diagram:

The sum of the two interior angles is equal to the exterior angle.

40 + 12k + 10 = 8k + 80

4k = 30

k = 30/4 = 15/2

Thus, in the first diagram the value of k is 10 and in the second diagram the value of k is 15/2.

Learn more about the triangle here:

brainly.com/question/25813512

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