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iragen [17]
3 years ago
14

If a polynomial function f(x)has root -2 + square root 8 and 9 what must be a factor of f(x)

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

Step-by-step explanation:

Given that f(x) is a polynomial function.

This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.

Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)

i.e. If -2+\sqrt{8} is a root, then -2-\sqrt{8} is also a root.

(Because this only when multiplied will make coefficients rational)

So the factors of f(x) should be atleast

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

There can be other factors also but this is compulsory

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3 years ago
1. Which would be a more helpful for solving the system: adding the two equations or subtracting
ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

\frac{2x+1}{2y}=7\\\\

Equation 2:

\frac{6x-1}{2y}=5

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\  with\ 6\\\\12x+6=84y

Now for the second equation:

\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y

Now subtracting equation 2 from equation 1

12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y

now insert this value of y into any equation

lets insert it into equation 1

\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375

5 0
3 years ago
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