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iragen [17]
2 years ago
14

If a polynomial function f(x)has root -2 + square root 8 and 9 what must be a factor of f(x)

Mathematics
1 answer:
Rasek [7]2 years ago
7 0

Answer:

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

Step-by-step explanation:

Given that f(x) is a polynomial function.

This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.

Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)

i.e. If -2+\sqrt{8} is a root, then -2-\sqrt{8} is also a root.

(Because this only when multiplied will make coefficients rational)

So the factors of f(x) should be atleast

(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)

There can be other factors also but this is compulsory

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Angle m AOC=108° m AOB=3x+4° m BOC=8x-28°<br><br> Find m AOB
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Hello from MrBillDoesMath!

Answer:

40



Discussion:

A diagram is always appreciated!

Assuming that

mAOC = mAOB    + mBOC       =>

108      = (3x + 4)  +  (8x - 28)    =>  combine common terms

108      = (3x + 8x) + (4 - 28 )     =>

108      = 11x - 24                        =>   add 24 to both sides

132     = 11x                                 =>

x = 132/11 = 12


So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40



Thank you,

MrB

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