Answer:
2
Step-by-step explanation:
Using the rule of radicals
×
⇔
, then

= 
=
× 
= 2
Answer:
(a)Revenue function,
Marginal Revenue function, R'(x)=580-2x
(b)Fixed cost =900
.
Marginal Cost Function=300+50x
(c)Profit,
(d)x=4
Step-by-step explanation:
<u>Part A
</u>
Price Function
The revenue function

The marginal revenue function

<u>Part B
</u>
<u>(Fixed Cost)</u>
The total cost function of the company is given by 
We expand the expression

Therefore, the fixed cost is 900
.
<u>
Marginal Cost Function</u>
If 
Marginal Cost Function, 
<u>Part C
</u>
<u>Profit Function
</u>
Profit=Revenue -Total cost

<u>
Part D
</u>
To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

The number of cakes that maximizes profit is 4.
Answer:
z = 3.3
Step-by-step explanation:
Given
2.2 = z - 1.1 ( add 1.1 to both sides )
3.3 = z
X/4 = 8
multiply both sides by 4 to get the value of x
x=32
Answer:

Step-by-step explanation:
<u><em>The correct question is</em></u>
1x10 to the fifth power over 4x10 to the negative fourth power given on scientific notation
we know that
To divide two numbers in scientific notation, divide their coefficients and subtract their exponents.
we have
