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Mashcka [7]
3 years ago
15

A cone has a height of 7ft and a radius of 4ft which equation can find the volume of the cone v=1.3 (7.2)

Mathematics
1 answer:
Margaret [11]3 years ago
4 0

Answer:

The volume of a cone is:

V=(hπr^2)/3, where h=height and r=radius  

V=(7π4^2)/3

V=112π/3 ft^3

V≈117.29 ft^3  (to nearest hundredth of a cubic foot)

Step-by-step explanation:

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Ber [7]

Answers:

  1. True
  2. False
  3. True

==========================================================

Explanation:

Point A is at (-3, 4). If we apply the translation rule of "shift 9 units to the right and 6 units down", then we apply this transformation

(x,y) \to (x+9,y-6)

We add 9 to the x coordinate and subtract 6 from the y coordinate.

So (-3,4) becomes (-3+9, 4-6) = (6, -2) which is where point A' is located in the diagram. You should find that points B,C,D all map to B', C', D' following this same translation rule.

Therefore, statement 1 is true.

Statement 3 is the same idea, but the order has been swapped. The order doesn't matter in this case. So that makes statement 3 true as well.

-----------------------------------------------

Statement 2 on the other hand is false

Why? Because a reflection reverses the orientation of a figure. Note how both squares ABCD and A'B'C'D' all go clockwise when we go through the alphabet (ie A to B to C to D).

If a reflection happened, then A'B'C'D' would go counterclockwise and show that the orientation has been swapped. I recommend drawing an analogue clock and going up to a mirror to see that the orientation has swapped.

To swap the orientation back, you need a second reflection. This shows that two reflections either lead to a translation or a rotation (depending if the mirror lines are parallel or not).

If you wanted, you could track to see where point B ends up if you follow statement 2. Point B is at (-1, 4). Reflect over the y axis to get to (1, 4). Then shift 6 units down to arrive at (1, -2) which is not the correct location of B'. The diagram shows B' is actually at (8, -2). So this is an alternative way to see how statement 2 is false.

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Answer:

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Step-by-step explanation:

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Solve: 10 2/3+2h≤4 1/3
PtichkaEL [24]

Answer:

\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}

Step-by-step explanation:

\text{First convert the mixed numbers to the improper fractions:}\\\\10\dfrac{2}{3}=\dfrac{10\cdot3+2}{3}=\dfrac{32}{3}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{13}{3}\\\\\text{Solve the inequality}\\\\10\dfrac{2}{3}+2h\leq4\dfrac{1}{3}\\\\\dfrac{32}{3}+2h\leq\dfrac{13}{3}\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{32}{3\!\!\!\!\diagup_1}+3\cdot2h\leq3\!\!\!\!\diagup^1\cdot\dfrac{13}{3\!\!\!\!\diagup_1}\\\\32+6h\leq13\qquad\text{subtract 32 from both sides}\\\\6h\leq-19\qquad\text{divide both sides by 6}\\\\h\leq-\dfrac{19}{6}

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Consider the matrices. what are the dimensions of the project matrix of two of these matrices​
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