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Anarel [89]
3 years ago
13

Gabriel lives and works in Michigan, which has a flat state income tax of

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer:4,050

Step-by-step explanation:

Withholding Rate: 4.25% | Personal Exemption: $4,400 | 2019 Michigan Income Tax Withholding Tables. Withholding Rate: 4.25% | Personal Exemption: $4,050 | 2019 Michigan Income Tax Withholding Tables.

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2,5,5,7,8<br> Find the mode
anastassius [24]
5 because it appears most
Mode is most
4 0
3 years ago
Read 2 more answers
1. The temperature in Chicago is 10°F. The temperature drops 15°F overnight. What is the temperature in the morning? SIN​
Damm [24]

Answer:

-5

Step-by-step explanation:

10 minutes 15 equals -5

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3 years ago
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On April 1, the price of gas at Bob's Corner Station was $3.35 per gallon. On May 1, the price was $3.85 per gallon. On June 1,
Zina [86]
<h2>Answer:</h2>

1. Between April 1 and May 1, Bob's price incrdased by <u>$0.50 or 15%</u>.

2. Between May 1 and June 1, Bob's price decreased by <u>$0.50 or 13%</u>.

3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is <u>$0.1 more expensive</u> when gas costs $3.85 than when gas costs $3.35.

4. Suppose the Fed raises the target for the federal fundsb rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately <u>0.25%</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Between April 1 and May 1, Bob's price incrdased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.35}  =0.15=15%.

<h3>2. Between May 1 and June 1, Bob's price decreased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.85}  =0.13=13%.

<h3>3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is (blank) when gas costs $3.85 than when gas costs $3.35.</h3>

<em>In this question we are looking for the difference of a difference. </em>

<em>If the proces across the street are always 20% higher, to find how much the gallon costs just multiply the price by 1.20, to increase 0.2 or 20%:</em>

$3.85 * 1.20= $4.62.

<em>Now, to see how much expensive this price is compared to Bob's, take de difference between the prices:</em>

$4.62 - $3.85= $0.77.

<em>Do the same to find the difference between the gas prices when the price is $3.35.</em>

$3.35 * 1.20= $4.02.

$4.02 - $3.35= $0.67.

Now, find the difference of those differences:

$0.77 - $0.67= $0.1.

<h3>4. Suppose the Fed raises the target for the federal funds rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately (blank).</h3>

<em>Find the difference between percentages:</em>

2.25% - 2%= 0.0225 - 0.02= 0.0025= 0.25%.

<em>Simpler method:</em>

2.25% - 2%= 0.25%.

3 0
2 years ago
PLZ HELP<br><br>1.2(j+3.5)≥4.8​
kvv77 [185]

Answer:

j≥-4

Step-by-step explanation:

HSHSHDJENDBDK SORRY IF THIS IS WRONG THIS IS MY FIRST TIME

5 0
2 years ago
Matrices A and B are square matrices of the same size. Prove Tr(c(A + B)) = C (Tr(A) + Tr(B)).
alexira [117]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))=C\cdot Sum of diagonal elements of A

C(Tr(B))=C\cdot Sum of diagonal elements of B

C(A+B)=C\cdot (A+B)

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]

B=\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

A+B=\left[\begin{array}{ccc}2&1\\2&2\end{array}\right]

C(A+B)=\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right]

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

5 0
3 years ago
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