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3 years ago

What is 0.0162 as a fraction

1 answer:

5 0

You have to ask yourself how would you read that decimal? It is 162 ten-thousandths because the last digit, which is 2 is in the ten-thousandths place. So the fraction would be 162/10000

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Brian invests $10,000 in an account earning 4% interest, compounded annually for 10 years. Five years after Brian's initial inve

Lena [83]

Brian will get 40,000 then Chris will get 70,000

8 0

3 years ago

Read 2 more answers

Suppose a car going 65 mph is traveling north parallel to a train going 50 mph. Once the front of the car is as far north as the

scoray [572]

Answer:

0.75 Miles

Step-by-step explanation:

To find the answer we have to find the difference in the distance the train and car travelled

65/60 is 1.083333 which is miles per minute then multiplied by 3 is 3.25 mile gone in 3 minutes

For the train it is 50/60 which is 0.833333 and the times 3 is 2.5 miles in three minutes

3.25 miles minus 2.5 miles is 0.75 miles so that is how long the train is

6 0

3 years ago

What is the solution to the equation 4 + = 6? y = 1 y = 4 y = 500 y = 2000

Lerok [7]

Step-by-step explanation:

pls make did make sense, darling!!

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2 years ago

Color blindness is an inherited characteristic that is more common in males than females. Let F represent female, and C represen

malfutka [58]

Answer:

0.513 = 51.3% probability of being a female.

Step-by-step explanation:

We are given the following formula:

$P(F \cup C) = P(F) + P(C) - P(F \cap C)$

In which:

Event F: Female

Event C: Red-green color blindness.

Probability of a Female

We have to find P(F), which is given by:

$P(F) = P(F \cup C) + P(F \cap C) - P(C)$

We are given by:

$P(C) = 0.039, P(F \cap C) = 0.004, P(F \cup C) = 0.548$

$P(F) = P(F \cup C) + P(F \cap C) - P(C) = 0.548 + 0.004 - 0.039 = 0.513$

0.513 = 51.3% probability of being a female.

5 0

3 years ago

I need help solving for x: log x = 2.46 - 1.12 * log y

Mariulka [41]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\\\\\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)
\\\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{log cancellation rule}\\\\
-----------------------------\\\\$

$\bf log(x)=2.46-1.12log(y)\iff log_{10}(x)=2.46-1.12log_{10}(y)
\\\\\\
log_{10}(x)=2.46-log_{10}(y^{1.12})\implies log_{10}(x)+log_{10}(y^{1.12})=2.46
\\\\\\
log_{10}(x\cdot y^{1.12})=2.46\implies 10^{\cfrac{}{}log_{10}(x\cdot y^{1.12})}=10^{2.46}
\\\\\\
xy^{1.12}=10^{2.46}\implies \boxed{x=\cfrac{10^{2.46}}{y^{1.12}}}$

8 0

4 years ago