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kondor19780726 [428]
2 years ago
6

If there is a wall that is nine feet tall and eleven feet wide, how many eight-by-ten inch picture frames can I put up? (Note: T

he pictures should not overlap and there might be some blank space left over.)
Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
6 0

The number of picture frames he can put on the wall is 178 picture frames.

The wall is rectangular and it is 9 feet tall and 11 feet wide.  let covert to inches.

9 feet = 108 inches

11 feet = 132 inches

<h3 /><h3>What is area:</h3>

The area is the space occupied by 2 dimensional figure. Let's find the area of the wall. Therefore,

area = lw

area = 108 × 132 = 14256  inches²

Therefore, let's find the area of the each picture frame. The frame is 8 inches by 10 inches.

area = 8 × 10 = 80 inches²

The number of picture you can put on the wall can be computed as follows:

  • 14256 / 80 = 178.2

He can put 178 pictures on the wall.

learn more on area here: brainly.com/question/14442082?referrer=searchResults

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Step-by-step explanation:

Las respuestas son fáciles:

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$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

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$ \sqrt{-4} = 2i $ .

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