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alukav5142 [94]
4 years ago
14

What is Y squared plus 5Y plus 2Y squared minus 4Y

Mathematics
1 answer:
Oksana_A [137]4 years ago
7 0
Y^2 + 5Y + 2Y^2 - 4Y= ?

add up the like terms
(Y^2 + 2Y^2) + (5Y - 4Y)=

=3Y^2 + 3Y
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if the lower pointvis 56 the dot line will be 55.5

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Can someone help me out my grade are bad
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Answer:

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Find the arc length of the partial circle.
Serga [27]

Known :

r = 5 cm

θ = 360° - 90° = 270°

Asked :

Arc length of the partial circle = ...?

Answer :

Arc length

=  \frac{θ}{360}  \times 2\pi r \\  =  \frac{270}{360}  \times 2 \times 3.14  \times 5 \\  =  \frac{3}{4}  \times 31.4 \\  =  \frac{3}{4}  \times  \frac{314}{10}  \\  =  \frac{942}{40}  \\  = 23.55 \: cm

So, the arc length of the partial circle is 23,55 cm

<em>Hope it helps and is useful</em><em> </em><em>:</em><em>)</em>

5 0
3 years ago
Can someone please help me find the domain, range, intercepts, and asymptotes pf this function?
marishachu [46]
1) given function

y = - 2 ^ ( -x + 2) + 1

2) domain: domain is the set of the x-values for which the function is defined.

The exponential function is defined for all the real numbers, so the domain of the given function is all the real numbers.

3) x-intercept => y = 0

=> y = - 2 ^ ( -x + 2) + 1 = 0 => 2^ ( -x + 2) = 1

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The x-intercept is x = 0

4) y-intercept => x = 0

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5) limit when x -> negative infinite

Lim f(x) when x -> ∞ = - ∞

6) limit when x -> infinite

Lim f(x) when x - > infinite = 1

=> asymptote = y = 1

7) range is the set of values of the fucntion: y

Given that the function is strictly decreasing from -∞ to ∞, the range is from - ∞ to less than 1

Range (-∞,1)


3 0
3 years ago
Simplify this expression: cos theta/ tan theta cot theta
Dmitry_Shevchenko [17]
Q: \frac{cos\theta}{tan\theta.cot\theta}=?

A:

\frac{cos\theta}{tan\theta.cot\theta}=cos\theta

because... tan\theta.cot\theta=1
*********************************************************
Q: \frac{cos\theta}{tan\theta}.cot\theta=?

A:

\frac{cos\theta}{tan\theta}.cot\theta&= \\  \\ \frac{cos\theta}{\frac{sin\theta}{cos\theta}}.\frac{cos\theta}{sin\theta}&= \\  \\ \frac{cos^2\theta}{sin\theta}}.\frac{cos\theta}{sin\theta}&= \\  \\ \frac{cos^3\theta}{sin^2\theta}}&= cos^3\theta.cosec^2\theta
5 0
4 years ago
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